17. What are the minimum, first quartile, median, third quartile, and maximum of the data set? 40, 7, 2, 35, 12, 23, 18, 28
Rzqust [24]
First step! Arrange the numerals {<span>40, 7, 2, 35, 12, 23, 18, 28} in ascending order: {2, 7, 12, 18, 23, 28, 35, 40}
Count these numerals: there are 8 (an even number)
To find the median of this set of numerals, take the middle 2 values {18, 23} and average them: median = (18+23)/2 = 41/2
Now, on the left of 41/2, we have the subset {2, 7 , 12, 18}. The median of this subset is found in the same way as was 41/2 (above):
(7+12)/2 = 19/2 (First quartile)
The median of the right subset {</span>23, 28, 35, 40} is (28+35)/2, or 63/2. This is the 3rd quartile.
The max. is 40 (this is the largest numeral given).
Subtract 2 3/4 from each side. You should get 3 2/5x = 17/4. Then, divide each side by 3 2/5. X = 5/4
Mean is average 11 x 2 = 22
The two cards need to equal 22 when added together.
the difference is 6:
6/2 = 3
11-3 = 8
11+ 3 = 14
14 +8 = 22
the two numbers are 8 and 14
Try number 1 hope it’s correct
