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mario62 [17]
3 years ago
15

Write an expression in terms of x that represents the distance between ( 4 , 8 ) and ( x , 8 ) for x > 4 .

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

The distance between two points is the number of units between them

The expression that represents the distance between the points is x - 4

<h3>How to determine the expression</h3>

The points are given as: (4,8) and (x,8)

The distance (d) between points is calculated using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

d = \sqrt{(x - 4)^2 + (8 -8)^2}

Evaluate the difference

d = \sqrt{(x - 4)^2 + 0^2}

Evaluate the exponent

d = \sqrt{(x - 4)^2 + 0}

Evaluate the sum

d = \sqrt{(x - 4)^2}

Evaluate the exponent

d = x - 4

Hence, the expression that represents the distance between the points is x - 4

Read more about distance at:

brainly.com/question/7243416

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Pls help I need this now
miv72 [106K]
The answer is A to your question
4 0
3 years ago
25. An apple is launched directly upward at 64 feet per second from a platform 80 feet high. The equation for this
Viktor [21]

Answer:

a. 144 ft

b. 5 s

Step-by-step explanation:

h = -16t² + 64t + 80

a. This is a parabola, so the maximum height is at the vertex.

t = -64 / (2 × -16)

t = 2

h = -16(2)² + 64(2) + 80

h = 144

The apple reaches a maximum height of 144 ft.

b. 0 = -16t² + 64t + 80

0 = t² − 4t − 5

0 = (t + 1) (t − 5)

t = -1 or 5

t must be positive, so it takes 5 seconds to reach the ground.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=26%20-%202%2810%20-%201%29%20%2B%20%283%20%2B%204%20%5Ctimes%2011%29" id="TexFormula1" title="
goldfiish [28.3K]

26-2\left(10-1\right)+\left(3+4\cdot 11\right)

26-(2)(9)+3+(4)(11)

26-18+3+(4)(11)

8+3+(4)(11)

8+3+44

8+47

55

"55 is correct answer".

Hope this helps!

Thanks!

-Charlie

5 0
3 years ago
Help....................................DDDDDDDDDDDDDDDDDDDDDDDDDDD
m_a_m_a [10]

Answer:

Step-by-step explanation:

a). Since, ΔABC ~ ΔWYZ

Their corresponding sides will be proportional.

\frac{AB}{WY}=\frac{BC}{YZ}= \frac{AC}{WZ}

\frac{194}{WY}=\frac{BC}{1}= \frac{130}{WZ}  --------(1)

By applying Pythagoras theorem in ΔABC,

AB² = AC² + BC²

BC² = AB² - AC²

BC² = (194)² - (130)²

BC² = 20736

BC = 144

From equation (1)

\frac{194}{WY}=\frac{144}{1}= \frac{130}{WZ}

\frac{194}{WY}=\frac{144}{1}

WY = \frac{194}{144}

WY = \frac{97}{72} = 1.35

\frac{144}{1}= \frac{130}{WZ}

WZ = \frac{130}{144}

WZ = \frac{65}{72} = 0.90

b). tan(A) = \frac{\text{Opposite side}}{\text{Adjacent side}}

               = \frac{144}{130}

               = \frac{72}{65}

Since, ΔABC ~ ΔWYZ,

∠A ≅ ∠W

Therefore, tangent of angle A and angle W will measure \frac{72}{65}.

8 0
3 years ago
Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b
4vir4ik [10]
The value of "b" is the y-intercept.

In order to figure out slope-intercept form you need 1 coordinate and the slope.
1) Find the slope, using the 2-point slope formula: "m= y2-y1 / x2-x1".
   ex. m= -5 - 3 / -4 - -6   (simplify)--->   m= -4

2) Fill in the blanks for point-slope formula: "y - y1 = m (x - x1)"
(choose one coordinate, it doesn't matter which one)
   ex. y - -5 = -4 (x - -4)

3) Then use basic algebra to simplify.


7 0
3 years ago
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