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lesya [120]
3 years ago
10

Differentiate with respect to x : 2xe^x​

Mathematics
1 answer:
Gnom [1K]3 years ago
7 0

\\ \sf\longmapsto \dfrac{d}{dx}2xe^x

  • Apply product rule

\\ \sf\longmapsto \dfrac{d}{dx}2x(e^x)

\\ \sf\longmapsto 2x\dfrac{d}{dx}e^x+e^x\dfrac{d}{dx}2x

\\ \sf\longmapsto 2xe^x+2e^x

\\ \sf\longmapsto 2e^x(x+1)

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7 0
3 years ago
Michelle is rolling two six-sided dice, numbered one through six. What is the probability that the sum of her rolls is 4? A. B.
Bad White [126]

Answer:

<h3>The probability that the sum of Michelle's rolls is 4 is 0.083 </h3><h3>∴ P(A)=0.083  </h3>

Step-by-step explanation:

Given that Michelle is rolling two six-sided dice, numbered one through six.

<h3>To find the probability that the sum of her rolls is 4:</h3>

s={\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\}

<h3>∴ n(s)=36</h3>

Let P(A) be the probability that the sum of her rolls is 4

Then the possible rolls with sums of 4 can be written as

A={\{(1,3),(2,2),(3,1)}\}

<h3>n(A)=3</h3>

The probability that the sum of her rolls is 4 is given by

P(A)=\frac{n(A)}{n(s)}

=\frac{3}{36}

=\frac{1}{12}

=0.083

<h3>∴ P(A)=0.083 </h3><h3>∴ the probability that the sum of Michelle's rolls is 4 is 0.083 </h3>
5 0
3 years ago
Brainly for correct -- step by step answer &lt;3
Arturiano [62]

Answer:

can you take a better pic so i can help

Step-by-step explanation:

8 0
3 years ago
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Identify a and b for the hyperbola with equation
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Answer:

identify a and b for the hyperbola with equation

7 0
3 years ago
Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).
lesya [120]

Answer:

-7x + 4y = +42

Step-by-step explanation:

Going from point (2, -7) to point (6, 0), x increases by 4 and y increases by 7.  Thus, the slope of the line in question is m = 7/4.

Starting from the equation y = mx + b, and subbing (7/4) for m, 6 for x and 0 for y, we get:

0 = (7/4)(6) + b.  Then b = 42/4, or 21/2.  Thus, we now have y = (7/4)x + 21/2.

We must put this into "standard form."  Multiplying all three terms by 4, we get:

4y = 7x + 42.  Rearranging these terms to fit the "standard form" equation Ax + By = C, we get:

-7x + 4y = +42

5 0
3 years ago
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