Answer:
The limit that 97.5% of the data points will be above is $912.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the limit that 97.5% of the data points will be above.
This is the value of X when Z has a pvalue of 1-0.975 = 0.025. So it is X when Z = -1.96.
So




The limit that 97.5% of the data points will be above is $912.
2. .8333333 repeated 3x1\3 is 1 the 1x5\6 is .83
3. Order of operations PMDOS 30\2 first giving you 15 then take 50-15=35
4. 10x1.5=15
5. 20+30 first because of order of operations then multiply by 10 giving you 500
6. 120 \ 12 = 10
7. 1 + 9 = 10
8. 0.15-0.02=.13x100 = 13
9. 4.9/0.07=70
Both A and B im pretty sure. they all have the same no matter