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Leya [2.2K]
3 years ago
12

The population full-time equivalent number of students (FTES) at Lake Tahoe Community College for 2005-2006 through 2010-2011 wa

s given in an updated report. The data are reported here. Year 2005-06 2006-07 2007-08 2008-09 2009-10 2010-11 Total FTES 1,585 1,690 1,735 1,935 2,021 1,890 Calculate the mean, median, standard deviation, the first quartile, the third quartile and the IQR. Round to one decimal place.
Mathematics
1 answer:
makkiz [27]3 years ago
8 0

The mean of the set of numbers that are given in this situation regarding the population will be 1809.33.

<h3>How to solve the mean</h3>

The mean of the numbers will be:

= (1,585 + 1,690 + 1,735 + 1,935 + 2,021 + 1,890) / 6

= 1809.33

The median of the numbers will be:

= (1735 + 1890) / 2

= 1812.50

Also, from the complete question, the first quartile will be 1690 and the third quartile is 1935.

Learn more about mean on:

brainly.com/question/20118982

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Three hundred and eighty -two tenthousandths
AlladinOne [14]

Answer:

382000

Step-by-step explanation:

8 0
3 years ago
.............Help Please...
rewona [7]

the answer is the second option (-5,1)

6 0
3 years ago
A researcher wishes to estimate the proportion of adults who have​ high-speed Internet access. What size sample should be obtain
Kamila [148]

Answer:

Step-by-step explanation:

Solution:-

- The sample size = n

- The Error of estimation, E = 0.04

- The confidence level, CI = 99%

a)

What size sample should be obtained when she uses previous estimate of p = 0.52​?

- We are given the sample proportion p = 0.52, the required sample size is a function of confidence value and error of estimation (E):

                 n = p*( 1 - p ) * (\frac{Z-critical}{E})^2

Where,

- The critical value of the confidence level = 99% would be:

           significance level ( α ) = 1 - CI = 1 - 0.99 = 0.01

           Z-critical = Z_α/2 = Z_0.005 = 2.575  

- The required sample size (n) can be calculated:

            n = 0.52*( 1 - 0.52 ) * (\frac{2.575}{0.04})^2\\\\n = 0.2304*(51.5)^2 = 611.0784

- Hence, the minimum required sample size (n) should be = 612 adults.  

b)

- If the preliminary estimate of proportion is missing or not given, we are to assume the proportion p = 0.5.

- Similarly, repeat the calculations for sample size (n) when p = 0.5

               n = 0.5*( 1 - 0.5 ) * (\frac{2.575}{0.04})^2\\\\n = 0.25*(51.5)^2 = 663.0625

- Hence, the minimum required sample size (n) should be = 664 adults.  

5 0
3 years ago
Pls help me find the absolute value of these<br>thanks in advance for any help.​
Studentka2010 [4]

Answer:

The absolute value or modulus of a real number x (denoted by |x| ) , is the non-negative value of x without regard to its sign.

3) |0| = 0

6) |-7| - |4|

=> 7 - 4 = 3

9) - | -101 | = -101

12) |8| - |-7|

=> 8 - 7 = 1

6 0
3 years ago
A swimming school claimed that the average seven-year-old would be able to swim across an Olympic-sized pool in less than 120 se
ddd [48]

Answer:

Step-by-step explanation:

The mean of the set of data given is

Mean = (60 + 120 + 110 + 80 + 70 + 90 + 100 + 130)/8 = 95

Standard deviation = √(summation(x - mean)/n

n = 8

Summation(x - mean) = (60 - 95)^2 + (120 - 95)^2 + (110 - 95)^2 + (80 - 95)^2 + (70 - 95)^2 + (90 - 95)^2 + (100 - 95)^2 + (130 - 95)^2 = 4200

Standard deviation = √(4200/8) = 22.91

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ ≤ 120

For the alternative hypothesis,

µ > 120

This is a right tailed test.

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 8,

Degrees of freedom, df = n - 1 = 8 - 1 = 7

t = (x - µ)/(s/√n)

Where

x = sample mean = 95

µ = population mean = 120

s = samples standard deviation = 22.91

t = (95 - 120)/(22.91/√8) = - 3.09

We would determine the p value using the t test calculator. It becomes

p = 0.009

Since alpha, 0.05 > than the p value, 0.009, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average seven-year-old would be able to swim across an Olympic-sized pool in more than 120 seconds after taking lessons from their instructors.

4 0
4 years ago
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