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LuckyWell [14K]
3 years ago
12

Can someone help me with this exercise?

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

View image

Step-by-step explanation:

You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.

Your first goal is to solve for y, which I did at the top.

And remember that when you divide/multiply by a negative number you have to flip the inequality sign.

So the first equation is already in term of y. (y < 2x + 4)

So you only have to solve for y for -3x - 2y ≥ 6.

I solved that and got y ≤ -3/2x - 3.

Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3

First you gotta treat it like a normal equation and graph them.

So i graphed y = 2x + 4 and y = -3/2x - 3. I assume you already know how do do that.

btw. < and > have dotted lines, while ≤ and ≥ have solid lines.

Now for the shading, you gotta look at the inequality sign.

y < 2x + 4 has a less than sign, so you have to shade everything underneath the line you graphed.

y ≤ -3/2x - 3 is also less than, so you have to shade everything underneath that line as well.

So in the future, you you get a > or ≥ then you have to shade above the graph.

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Answer:

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Step-by-step explanation:

In order to solve this problem we need to know the vertex and the direction its pointing.

First we expand,

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Now we plug 3 in the equation to get the y value,

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The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.

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