To get which design would have maximum area we need to evaluate the area for Tyler's design. Given that the design is square, let the length= xft, width=(120-x)
thus:
area will be:
P(x)=x(120-x)
P(x)=120x-x²
For maximum area P'(x)=0
P'(x)=120-2x=0
thus
x=60 ft
thus for maximum area x=60 ft
thus the area will be:
Area=60×60=3600 ft²
Thus we conclude that Tyler's design is the largest. Thus:
the answer is:
<span>Tyler’s design would give the larger garden because the area would be 3,600 ft2. </span>
Answer:
Part a) Rectangle
Part b) Triangle
Step-by-step explanation:
Part A) A cross section of the rectangular pyramid is cut with a plane parallel to the base. What is the name of the shape created by the cross section?
we know that
When a geometric plane slices any right pyramid so that the cut is parallel to the plane of the base, the cross section will have the same shape (but not the same size) as the base, So, in the case of a right rectangular pyramid, the cross section is a rectangle
Part b) If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what would be the shape of the resulting cross section?
we know that
Cross sections perpendicular to the base and through the vertex will be triangles
Answer:
y = x/4 + 5
Step-by-step explanation:
Solve for y:
20 - 4 y = -x
Hint: | Isolate terms with y to the left-hand side.
Subtract 20 from both sides:
-4 y = -x - 20
Hint: | Solve for y.
Divide both sides by -4:
Answer: y = x/4 + 5
