Using Sin^2 and Cos^2 identities,
= Cos^2(2A) + 4[(1/2)(1-Cos(2A)][(1/2)(1+Cos(2A)] = 1
= Cos^2(2A) + 1 -Cos^2(2A) = 1
0 = 0
There is nothing to solve for as it is an identity of sorts.
Answer:
72
Step-by-step explanation:
(a+b/2)h
(4+12/2)9 = 72
Answer:
3x ^3 +4x^2 −2
Step-by-step explanation:
STEP
1
: Equation at the end of step 1
(((5•(x3))+(3•(x2)))+1)-((2x3-x2)+3)
STEP 2 Equation at the end of step
(((5•(x3))+3x2)+1)-(2x3-x2+3)
STEP 3 :
Equation at the end of step
((5x3 + 3x2) + 1) - (2x3 - x2 + 3)
STEP
4:
Polynomial Roots Calculator :
4.1 Find roots (zeroes) of : F(x) = 3x3+4x2-2
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 3 and the Trailing Constant is -2.
The factor(s) are:
of the Leading Coefficient : 1,3
of the Trailing Constant : 1 ,2
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 -1.00
-1 3 -0.33 -1.67
-2 1 -2.00 -10.00
-2 3 -0.67 -1.11
1 1 1.00 5.00
1 3 0.33 -1.44
2 1 2.00 38.00
2 3 0.67 0.67
Hope This Helps
