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wel
2 years ago
8

Please help me with this problem. I'm kind of stuck and don't know what to do.

Mathematics
1 answer:
Flauer [41]2 years ago
8 0

Try this option:

1) if csc(u)=9, then 1/sin(u)=9 and sin(u)=1/9;

2) if sin(u)=1/9, then cos(u):

cos(u)=\sqrt{1-sin^2(u)}=\sqrt{1-\frac{1}{81}}=\frac{4\sqrt{5}}{9};

3) if \ sin(u)=\frac{1}{9} \ and \ cos(u)=\frac{4\sqrt{5}}{9}, then

sin(2u)=2sin(u)*cos(u)=\frac{8\sqrt{5}}{81};

cos(2u)=cos^2(u)-sin^2(u)=\frac{80}{81}-\frac{1}{81}=\frac{79}{81};

tan(2u)=\frac{sin(2u)}{cos(2u)}=\frac{\frac{8\sqrt{5}}{81}}{\frac{79}{81} }=\frac{8\sqrt{5}}{79}.

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P =  - 1 1/4
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3 years ago
What is the equation of this line?
andrew-mc [135]
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\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =  \frac{y_{1}-y_{2}}{x_{1}-x_{2}}
Plugging this in for our points, we get \frac{0-5}{10-0} = -5/10=-1/2 as our slope (we get -1/2 by dividing both -5 and 10 by 5 from the previous fraction), making our equation y=(-1/2)x+b. Plugging a point in to find out what b is, we get 0=(-1/2)10+b=-5+b. Adding 5 to both sides to separate the b, we get 5=b, making our equation y=(-1/2)x+5. To find out what x is for (x,2), since the y value comes second, we can plug in 2 into our equation to get 2=(-1/2)x+5. Since we want to solve for x, we have to separate it. Subtracting 5 from both sides, we get -3=(-1/2)x. Since we can multiply -1/2 by its reciprocal (switching the numerator and denominator) to get 1 (and therefore x on the right sides as 1*x=x), we multiply both sides by -2 to get 6=x, making the point (6,2)

Feel free to ask further questions!
4 0
3 years ago
I’m stuck on this question can anyone help me?
ch4aika [34]

Answer: REE thats high school work

Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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2 years ago
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shusha [124]
ANSWER:
In triangles BEC and AED
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3 years ago
Read 2 more answers
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