X=y+3
<span>-5x-4y=<span>30
-------------------
Substitute y + 3 for x in </span></span>-5x-4y=30
<span><span>-5<span>(y+3)-</span></span>4y</span>=<span>30
</span>-9y-15=<span>30
</span>----------------------------
Add 15 to each side
<span><span>-9y-15</span>+15</span>=<span>30+<span>15
-9y = 45
</span></span>-----------------------------------
Divide each side by -9
-9y ÷ -9 = 45 ÷ -9
y = -5
Now we solve for x
====================================================================
Substitute -5 for y in x = y + 3
x=-<span><span>5</span>+<span>3
</span></span>x = -2
----------------------
(-2,-5) is your answer
Tn = a + (n-1)d
when n = 12, tn = 63
63 = a + (12-1)*5
a = 63 - 55 =8
tn or an
= 8 + (n-1) 5
= 3 + 5n
Hope this helps
Answer:
19
Step-by-step explanation:
fx=16+4
fx=20
gx= 20-1
gx=19
19
Answer:
x³ - (√2)x² + 49x - 49√2
Step-by-step explanation:
If one root is -7i, another root must be 7i. You can't just have one root with i. The other roos is √2, so there are 3 roots.
x = -7i is one root,
(x + 7i) = 0 is the factor
x = 7i is one root
(x - 7i) = 0 is the factor
x = √2 is one root
(x - √2) = 0 is the factor
So the factors are...
(x + 7i)(x - 7i)(x - √2) = 0
Multiply these out to find the polynomial...
(x + 7i)(x - 7i) = x² + 7i - 7i - 49i²
Which simplifies to
x² - 49i² since i² = -1 , we have
x² - 49(-1)
x² + 49
Now we have...
(x² + 49)(x - √2) = 0
Now foil this out...
x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0
x³ + (√2)x² + 49x - 49√2
Since this is numberical data graph it as a line graph
