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Natasha2012 [34]

2 years ago

5

Calculate the frequency of light that has a wavelength of

1 answer:

dybincka [34]2 years ago

7 0

Answer:

The velocity of light, v, is the product of its wavelength, λ , and its frequency, f. This means that the wavelength is the velocity, v, divided by the frequency, f.

Wavelength of light = velocity of light / frequency of light

λ = v/f

λ = Wavelength of light, meters

v = Velocity of light (c = 3.0 x 108 m, for speed of light if not otherwise defined)

f = frequency of light, Hz

Step-by-step explanation:

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What is 55> -7v +6 plzz help, this my homework

Vanyuwa [196]

The answer is v>7 Because when solving the equation you do inverse operation on 6 which be negative six .Then subtract negative 6 on both sides.
Next you bring down negative 7v along with the solution to 55-6 which is 47.Then you divide 7 on both sides which gives you 7.Then bring down the v
and it give the solution of v>7

Hope this helps stacey:)

8 0

3 years ago

What is the slope of a line that is parallel to the line shown

Angelina_Jolie [31]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Parallel lines have the same slope

The slope of the line shown is $\frac{1}{4}$

Therefore, the slope of the parallel line will also be $\frac{1}{4}$

3 0

3 years ago

Find the exact value of tan A in simplest radical form.

spin [16.1K]

Answer:

$tan(A) = \frac{2\sqrt{15}}{11}$

Step-by-step explanation:

Given:

Right ∆ABC

AB = 61

BC = 60

AC = 11

Required:

Value of tan A in radical form

SOLUTION:

$tan(A) = \frac{opposite}{adjacent}$

Opposite = 60

Adjacent = 11

$tan(A) = \frac{60}{11}$

$tan(A) = \frac{\sqrt{4*15}}{11}$

$tan(A) = \frac{2\sqrt{15}}{11}$

6 0

3 years ago

One airplane located 200km north and 50km east of an airport. A second plane at the same altitude is located 30km north and 100k

grigory [225]

Answer: 350

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

(5a^2+6a+2)-(7a^2-7a-5)

krok68 [10]

For this case we must simplify the following expression: $(5a^ 2 + 6a + 2) - (7a^ 2-7a-5) =$

We eliminate the parentheses taking into account that:

$- * + = -\\- * - = +$

So:

$5a ^ 2 + 6a + 2-7a ^ 2 + 7a + 5 =$

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

$5a ^ 2-7a^2 + 6a + 7a +2 +5 =\\-2a ^ 2 + 13a + 7$

Answer:

$-2a ^ 2 + 13a + 7$

8 0

3 years ago