Question

You need a 25% alcohol solution. On hand, you have a 225 mL of a 35% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need____ mL of pure water to obtain___ mL of the desired 25% solution.

Answer 1

You will need 252 mL of pure water to obtain 0.25 mL of the desired 25% solution.

If we add X amount of water to the solution, the total amount of solution is 375+X.

And that must be 25%.

What is the amount of solute in the current solution?

The amount of solute in the current amount of solution is

0.6(375)=225.

That amount won't change by adding water.

So we set up the equation so that the amount of solute divided by the new total amount of solution equals 25%.

225/(375+X)=0.25

cross multiply and solve

225/0.25=(375+X)

900-375=X

X=525

The pure water will you need to add to obtain the desired solution is 525.

Then we check 225/(375+525)=0.25.

To learn more about the mixture problem visit:

brainly.com/question/24647756

#SPJ1