Question

PQRST is a rectangular-based pyramid with a height of 9cm.

Answer 1

Answer:

54.1° (1 dp)

Step-by-step explanation:

Let the center point of the rectangle PQRS = M

Calculate the length of the line SM using Pythagoras' Theorem:

          a² + b² = c²

(11/2)² + (7/2)² = SM²

              42.5 = SM²

                SM = √42.5 cm

The height of the pyramid is 9 cm,  therefore, MT = 9

Now we have a right angled triangle with base SM and height MT and hypotenuse ST

We want to find the angle TSM, so we can use the trig formula tan x = O/A, where x is the angle, O is MT and A is SM

tan TSM = MT/SM = 9/√42.5

TSM = arctan (9/√42.5) = 54.082088°

So the angle between the line ST and the plane PQRS = 54.1° (1 dp)