Answer: 14.2 - 5a
Work: I just did "CLT" of "Combine Like Terms". I did 8 + 6.2 First because 8 is first, then I did 4a - 9a which is -5a, and I combined them, and got the answer. I hope this helps, and stay safe! :)
Answer: 15
Step-by-step explanation: This is one of those square roots you'll memorize really quickly. You don't even have to simplify it, since it's an integer.
Step-by-step explanation:
![A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C5%267%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%261%5C%5C6%260%5Cend%7Barray%7D%5Cright%5D)
![C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]](https://tex.z-dn.net/?f=C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%261%5C%5C-1%260%264%5Cend%7Barray%7D%5Cright%5D)
![D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]](https://tex.z-dn.net/?f=D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%264%5C%5C0%26-2%261%5C%5C3%264%26-1%5Cend%7Barray%7D%5Cright%5D)
![1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]](https://tex.z-dn.net/?f=1.%5C%5CA%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C5%267%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%261%5C%5C6%260%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%2B4%261%2B1%5C%5C5%2B6%267%2B0%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%262%5C%5C11%267%5Cend%7Barray%7D%5Cright%5D)
![2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]](https://tex.z-dn.net/?f=2.%5C%5CB-A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%261%5C%5C6%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C5%267%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-3%261-1%5C%5C6-5%260-7%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C1%26-7%5Cend%7Barray%7D%5Cright%5D)
![3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]](https://tex.z-dn.net/?f=3.%5C%5C3C%3D3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%261%5C%5C-1%260%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%283%29%28-2%29%26%283%29%283%29%26%283%29%281%29%5C%5C%283%29%28-1%29%26%283%29%280%29%26%283%29%284%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%269%263%5C%5C-3%260%2612%5Cend%7Barray%7D%5Cright%5D)
![4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]](https://tex.z-dn.net/?f=4.%5C%5CC%5Ccdot%20D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%261%5C%5C-1%260%264%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%264%5C%5C0%26-2%261%5C%5C3%264%26-1%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-2%29%28-2%29%2B%283%29%280%29%2B%281%29%283%29%26%28-2%29%283%29%2B%283%29%28-2%29%2B%281%29%284%29%26%28-2%29%284%29%2B%283%29%281%29%2B%281%29%28-1%29%5C%5C%28-1%29%28-2%29%2B%280%29%280%29%2B%284%29%283%29%26%28-1%29%283%29%2B%280%29%28-2%29%2B%284%29%284%29%26%28-1%29%284%29%2B%280%29%281%29%2B%284%29%28-1%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-8%26-6%5C%5C14%2613%26-8%5Cend%7Barray%7D%5Cright%5D)

The dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
<h3>What is the Pythagoras theorem?</h3>
The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.
We have:
Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The other end of the leash is tied to the top of an 8-foot pole.
After drawing a right-angle triangle from the above information.
Applying Pythagoras' theorem:
60² = 6² + x²
After solving:
x = 59.69 ≈ 59.7 foot
Thus, the dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
Learn more about Pythagoras' theorem here:
brainly.com/question/21511305
#SPJ1
Computing an integral by substitution is the reverse of the chain rule for computing the derivative. Substitution is intended to rewrite a complicated-looking integral involving the derivative of some component expression as another much simpler integral. For example, if
, then
and

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Integration by parts is the reverse of the product rule for derivatives:

Integrating both sides with respect to
gives


###
Personally, I think the best way to grasp the idea behind the two methods is to practice. You start to notice patterns to the point where knowing which is the "right" method to use becomes second nature.