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iragen [17]
3 years ago
12

Determine the effects the transformation 8() = e' +3 has on the maximum and

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

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By solving substitution y=4x-6<br> Y= 5x how I need steps
stiv31 [10]

Answer:

x= -6

Step-by-step explanation:

y=4x-6

y=5x, so where ever you see y, put 5x there.

hence, 5x=4x-6

5x-4x=-6

x= -6

5 0
3 years ago
8 coins to equal $1.06
SVEN [57.7K]

Answer: 3 quarters is equal to .75 and 2 dimes is equal to .20

So far we have .95 with 5 coins

2 nickels which is equal to .10

1 penny

8 coins = 1.06

Step-by-step explanation:

7 0
3 years ago
A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Inez waters her plants every two days. She trims them every 15 days. She did both today. When will she do them both again?
shtirl [24]

The answer is 30 days.

The solution for this is to find the least common multiple. By getting the multiple of both numbers.

Multiples of 2:  2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40…..

Multiples of 15: 15,30,45,60,75……..

The Least Common Multiples of 2 and 15 is 30. So, Inez will do them both again in 30 days.

The least common multiple (LCM) of two numbers is the smallest number that is multiple by the both number.

7 0
3 years ago
What is the distance between the points (-1,-9) and (4,-2)?
Crank

\sqrt{74}, or 8.60

Just use the distance formula

4 0
3 years ago
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