Let the two integers be x and y
x-3= 2y
x=2y+3______(1)
x²+y²= 233_____(2)
sub eqn (1) into (2)
{2y+3}²+y²=233
4y² + 12y +9 +y²=233
5y²+12y+9-233=0
5y²+12y-224=0
y= -8 or 5.6
recall they are positive integers so y=5.6
now sub y=5.6 into eqn (1)
x=2(5.6)+3 = 11.2+3=14.2
the two integers are 14.2 and 5.6
Answer:
8
Step-by-step explanation:
6t - 20 - 32u = ?
t = 6 u = 1/4 [.25]
6*(6) - 20 - 32*(1/4)
36 - 20 - 8 = ?
? = 8
i hope this helps!
:)
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Answer:
(-1, -5)
Step-by-step explanation:
When you graph the points, you find that the lines intersect at the point (-1, -5). That is the solution to the system of equations.
(x, y) = (-1, -5)