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2 years ago

The area of a square is 14 square centimeters. What is the length of one side of the square?

Mathematics

2 answers:

Alex17521 [72]2 years ago

6 0

Answer: 7

Step-by-step explanation: if it a square then both side have to be same length so just divide 14 by 2 to get 7

hope this helps mark me brainliest please

user100 [1]2 years ago

5 0

Answer:

sqrt(14) units

Step-by-step explanation:

Area = side²

14 = side²

side = sqrt(14)

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6 = -5 -x solve for x

makkiz [27]

Answer:

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so that its value can be determined.

6 + x = -5

<h3>Step 2: Subtract 6</h3>

x = -11

<h3>Step 3: Check</h3>

6 = -5 - -11

6 = -5 + 11

6 = 6 ✔

<h3>Step 4: Answer</h3>

x = -11

I'm always happy to help :)

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3 years ago

Graph the line with 1/2 slope<br> passing through the point (-5,1).

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Answer:

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3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
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which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

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