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fiasKO [112]
3 years ago
14

What is the y-intercept of the line passing through the point (9,-7) with a slope of -1/8 ?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

(0, -47/8)

Step-by-step explanation:

sub. in y = mx + b

=> -7 = -1/8(9) + b

=> b = -7 + 9/8

=> b = 9/8 - 56/8

=> b = -47/8

makkiz [27]3 years ago
7 0

Answer:

-5 7/8

Step-by-step explanation:

We can construct a linear equation for this line, with the form y = mx + b, where m is the slope and b the y-intercept (the value of y when x = 0).

We're given slope of -(1/8), so:

y = -(1/8)x + b

To find b, the y-intercept, use the given pioint and solve for b:

y = -(1/8)x + b  for (9,-7)

-7 = -(1/8)*9 + b

-7 = -(9/8) + b

b = -7 + (9/8)

b = -5 7/8

The y-intercept is -5 7/8

See the attached graph.

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Let s = sale

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Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
Solve the quadratic equation:<br> 3x^2+x-5=0
adell [148]

3x²+x-5=0

a = 3, b = 1, c= -5

-> ∆ ( delta ) = b²-4ac = 61 > 0

-> x1 =( -b+√∆ )÷ 2a =...

x2 = (-b-√∆)÷2a =...

p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.

4 0
3 years ago
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