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Rzqust [24]
3 years ago
7

Please help! I'm raising the points to anyone that GIVES AN ANSWER- Answers such as "I'm just doing this for points" or "I don't

know I want to help you" will be reported.

Mathematics
1 answer:
Sever21 [200]3 years ago
4 0
180 = 72 + (2x) + x

subtract 72 from both sides.

108 = 3x

divide both sides by 3.

36 = x

m<DEF = 72*
m<EFD = 72*
m<EDF = 36*

M<FDG = 36 / 2 = 18 <<<<<<<
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100 points gor correct answer Identify the base of a triangle in which h=(3x+15) ft and A=(15x+75) ft^2.
ivolga24 [154]

Answer:

b = 10

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

Here h = 3x + 15 and A = 15x + 75, thus

\frac{1}{2} × b × (3x + 15) = 15x + 75

Multiply both sides by 2 to clear the fraction

b(3x + 15) = 30x + 150

Divide both sides by (3x + 15)

b = \frac{30x+150}{3x+15} ← factor numerator and denominator

  = \frac{30(x + 5)}{3(x+5)} ← cancel the factor (x + 5) on numerator/denominator

  = \frac{30}{3}

  = 10

7 0
2 years ago
Read 2 more answers
Which statement is true about the solution ?
Harrizon [31]

Answer:

There are no real solutions to this equation

Step-by-step explanation:

4 0
2 years ago
Braden has 3 soccer balls and 2 basketballs that weighs a total of 5.44 pounds. Which equation and solution can be used to deter
STALIN [3.7K]
3x+2y=5.44
it's a two variable problem which can't be solved algebraically unless you are given the weight of one of the balls.
8 0
2 years ago
Solve the simultaneous equations<br>4x+3y=1<br>4x^2+3xy+y^2=2​
Fantom [35]

Notice that the second equation,

4<em>x</em> ² + 3<em>xy</em> + <em>y</em> ² = 2

can be written as

<em>x</em> (4<em>x</em> + 3<em>y</em>) + <em>y</em> ² = 2

and the first equation says 4<em>x</em> + 3<em>y</em> = 1, so this reduces to

<em>x</em> + <em>y</em> ² = 2

Solve the first equation for <em>x</em> :

4<em>x</em> + 3<em>y</em> = 1

4<em>x</em> = 1 - 3<em>y</em>

<em>x</em> = (1 - 3<em>y</em>)/4

Substitute this into the reduced second equation to get a quadratic equation in <em>y</em>, which happens to be easily factorized and solved:

(1 - 3<em>y</em>)/4 + <em>y</em> ² = 2

1 - 3<em>y</em> + 4<em>y</em> ² = 8

4<em>y</em> ² - 3<em>y</em> - 7 = 0

(4<em>y</em> - 7) (<em>y</em> + 1) = 0

4<em>y</em> - 7 = 0   <u>or</u>   <em>y</em> + 1 = 0

<em>y</em> = 7/4   <u>or</u>   <em>y</em> = -1

Solve for <em>x</em> :

<em>x</em> = (1 - 3 (7/4))/4   <u>or</u>   <em>x</em> = (1 - 3 (-1))/4

<em>x</em> = -17/16   <u>or</u>   <em>x</em> = 1

So the two solutions are (<em>x</em>, <em>y</em>) = (-17/16, 7/4) and (<em>x</em>, <em>y</em>) = (1, -1).

8 0
2 years ago
1) Find the inverse function of f(x)=1/2x+3
dexar [7]
 y = 1/2x + 3
change x and y

x = 1/2y + 3
now find the value of y and that is inverse function 

x - 3 =1/2 y
y = 2x- 6
 
f-(x) = 2x - 6
<u />

for both domain : ( - ∞ , + ∞ )

range f (x) : ( - ∞ , + ∞ )  - { 0 }
range f-(x) :( -∞ , +∞)
8 0
3 years ago
Read 2 more answers
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