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GarryVolchara [31]

3 years ago

7

A group of 10 men who were recently diagnosed with testicular cancer recently gathered to share their feelings and provide mutua

l support. How many of these men will be alive to attend a group reunion in 5 years

1 answer:

sveta [45]3 years ago

7 0

5men because half of them would probably not make it

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I need help on 10 13 16

Zepler [3.9K]

$10.\\1ft=0.3048m\to1m=\dfrac{10000}{3048}ft\approx3.281ft\\\\therefore\ 14m\approx14\cdot3.28ft1=45.93ft$

$13.\\1mi=1.609km\to1km=\dfrac{1000}{1609}mi\approx0.621mi\\\\therefore\ 0.3km\approx0.3\cdot0.621mi=0.186mi$

$1in=2.54cm\to1cm=\dfrac{100}{254}in\approx0.394in\\\\therefore\ 15cm\approx15\cdot0.394in=5.91in$

3 0

3 years ago

Write an absolute value for all real numbers at least 3 units from -2

guajiro [1.7K]

<span>{<span>xi</span>,...}</span><span>|3|≥x</span>something like this

6 0

3 years ago

Suppose y varies directly with x and y=72 when x=6. what direct variation equation relates x and y? what is the value of y when

scoundrel [369]

Y=12x
Check: 72=12(6)
72=72
y=12x
y=12(10)
y=120
when x is 10 y is 120

6 0

3 years ago

Read 2 more answers

Write an equation that expresses the following relationship.

stepladder [879]

Answer:

w = $\frac{ku}{d^{2} }$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The formula W=0.86g^2-0.01g+5.9 models the weight, W, in ounces, for a cat who is fed g grams per day of a special food. Accordi

RUDIKE [14]

Using the equation which models weight of cat in terms of amount of food fed, the weight of the cat will be : 151.11 ounces

<u>Given the equation</u> :

W=0.86g² - 0.01g +5.9

<em>g = Amount of food in grams </em>

<u>Substituting g = 13 into the equation</u> :

W = 0.86(13)² - 0.01(13) +5.9

W = 0.86(169) - 0.13 + 5.9

W = 145.34 - 0.13 + 5.9

W = 151.11 ounces

Therefore, the weight of the cat will be 151.11 ounces

Learn more : brainly.com/question/18796573

7 0

2 years ago