2x² + 16x + 30
<span>Step 1: Solve the quadratic equation to get <span>x1</span> and <span>x2</span>.</span> In this example
we have: x₁ = −3 and x₂ = −5
Step 2: To find factored form we use formula
<span>ax</span>²+bx+c=a(x−x₁)(x−x₂)
<span>a=2 , b=16 , c=30 , <span>x1</span>=−3 , <span>x2</span>=−5
Substitute the values,
It would be: 2(x+3)(x+5)
In short, Your Answer would be Option BHope this helps!</span>
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Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
90/x=70/100 that's my answer