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3 years ago

13

Tickets to a show cost $5.50 for adults and $4.25 for students. A family is purchasing 2 adult tickets and 3 student tickets. Wh

at is the exact cost?

2 answers:

MArishka [77]3 years ago

8 0

Answer:

$23.75

........................

kramer3 years ago

4 0

Answer: $23.75

Step-by-step explanation:

$5.50a+$4.25s

$5.50(2)+$4.25(3)

= $23.75

a= is adult tickets

s=student tickets

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masha68 [24]

Answer:

C) $58,544

Step-by-step explanation:

the yearly tuition is $58,830 minus her scholarship of $44,194 leaves her with $14,636 to come up with so $14,636 times 4 equals $58,544

she needs $58,544 to attend this university for four years.

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3 years ago

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

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3 years ago

Daniel reads dor 8 times as many as April. Daniel read 44 minutes this week. How many minutes does April read?

ELEN [110]

44 [minutes] * 8 [times as many as April] = 352 [minutes in April]

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3 years ago

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We are first ask to translate this equation. So using the correct notation...

3X-9=6x6/4

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3x-9 = 6x6/4

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answer: X=6

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3 years ago