An investment is currently worth 1.2 x 10^7 dollars. Twenty years ago, the investment was worth 9.6 x 10^5 dollars.

Mathematics

2 answers:

NARA [144]4 years ago

4 0

Answer:

12.5

Step-by-step explanation:

Hope this helps!

Kazeer [188]4 years ago

3 0

Well your investment now is 12000000, and 20 years ago it was 960000. That pretty much answers your question.

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mestny [16]

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3 years ago

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Evaluate: -(-1) + (-7) + (2) - (-4) - (-2) A) -2 B) 0 C) 1 D) 2'

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Answer:

Step-by-step explanation:

-(-1) + (-7) + (2) - (-4) - (-2) =

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3 years ago

Two certificates of deposit pay interest that differ by 3%. Money invested for one year in the first CD earns $240 interest. The

Soloha48 [4]

a = interest rate of first CD

b = interest rate of second CD

and again, let's say the principal invested in each is $X.

$\bf a-b=3\qquad \implies \qquad \boxed{b}=3+a~\hfill \begin{cases} \left( \frac{a}{100} \right)X=240\\\\ \left( \frac{b}{100} \right)X=360 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \left( \cfrac{a}{100} \right)X=240\implies X=\cfrac{240}{~~\frac{a}{100}~~}\implies X=\cfrac{24000}{a} \\\\\\ \left( \cfrac{b}{100} \right)X=360\implies X=\cfrac{360}{~~\frac{b}{100}~~}\implies X=\cfrac{36000}{b} \\\\[-0.35em] ~\dotfill\\\\$

$\bf X=X\qquad thus\qquad \implies \cfrac{24000}{a}=\cfrac{36000}{b}\implies \cfrac{24000}{a}=\cfrac{36000}{\boxed{3+a}} \\\\\\ (3+a)24000=36000a\implies \cfrac{3+a}{a}=\cfrac{36000}{24000}\implies \cfrac{3-a}{a}=\cfrac{3}{2} \\\\\\ 6-2a=3a\implies 6=5a\implies \cfrac{6}{5}=a\implies 1\frac{1}{5}=a\implies \blacktriangleright 1.2 = x\blacktriangleleft$

$\bf \stackrel{\textit{since we know that}}{b=3+a}\implies b=3+\cfrac{6}{5}\implies b=\cfrac{21}{5}\implies b=4\frac{1}{5}\implies \blacktriangleright b=4.2 \blacktriangleleft$