Point slope form follows the equation y-y₁=m(x-x₁), so we want it to look like that. Starting off with m, or the slope, we can find this using your two points with the formula
. Note that y₁ and x₁ are from the same point, but it does not matter which point you designate to be point 1 and point 2. Thus, we can plug our numbers in - the x value comes first in the equation, and the y value comes second, so we have
as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m, and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be
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The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.
let the base of the triangle be x
Height of the triangle = x - 4
Area of triangle = 1/2 × base × height
Area = 1/2 × x × (x-4)
Area = 1/2 (x² - 4x)
Area = 1/2 x² - 2 x
We can also write it as a function:
y = 1/2 x² - 2 x
Domain = (3 , ∞)
Range = [0, ∞)
Since 3 is not included in the domain, base of the triangle cannot be 3 cm.
Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.
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Answer:
Step-by-step explanation:
Given
Required
Find all product of real values that satisfy the equation
Cross multiply:
Subtract 7 from both sides
Reorder
Multiply through by -1
The above represents a quadratic equation and as such could take either of the following conditions.
(1) No real roots:
This possibility does not apply in this case as such, would not be considered.
(2) One real root
This is true if
For a quadratic equation
By comparison with
Substitute these values in
Add 56 to both sides
Divide through by 4
Take square roots
Hence, the possible values of r are:
or 
and the product is:
For the first one we divide every element by sqrt3
we get
q+2/sqrt3 =sqrt5/sqrt3
q=(sqrt5-2)/sqrt3
q=sqrt3*sqrt5-2*sqrt3/3
q=sqrt15-2sqrt3/3
which is the third option
For the second one
sqrt(2y-5) +4=8
first we move the 4 to the right
sqrt(2y-5)=4
we remove the square root by bringing to the power of two
2y-5=16
2y=21
y=21/2
y=10 1/2
third option
Answer:
10
Step-by-step explanation:
