A function is a rule that assigns exactly one output to a given input. The input is taken from a set called the domain, and the corresponding output belongs to a set called the range.
1. In this exercise, we're calling the pool of patients 1-8 the domain, and the pool of nurses A-D the range. The given table describes a function because any patient is assigned to only one nurse.
2. This wouldn't be a function if at least one patient was assigned to more than one nurse. If this were to happen in practice, the patient could be, say, given the same dose of some medicine twice if the nurses aren't careful.
3. Making the nurse pool the domain and the patient pool the range would give a relation that is not a function, since more than one patient is assigned to one nurse.
Answer:
a:c = 35:24
a:c = 20:27
a:c = 35:22
a:c = 28:27
Step-by-step explanation:
a:b = 7:3
Using cross products
3a = 7b
Divide by 7
3a/7 = b
Now we want
8b = 5c
Substitute in 3a/7 for b
8 (3a/7) = 5c
24/7a = 5c
Multiply by 7
24/7a *7 = 5*7c
24a = 35c
Divide by c
24 a/c = 35
Divide by 24
a/c = 35/24
a:c = 35:24
a:b = 4:9
Using cross products
9a = 4b
Divide by 4
9a/4 = b
Now we want
3b = 5c
Substitute in 9a/4 for b
3 (9a/4) = 5c
27/4a = 5c
Multiply by 4
27/4a *4 = 5*4c
27a = 20c
Divide by c
27 a/c = 20
Divide by 27
a/c = 20/27
a:c = 20:27
b:c = 5:11
Using cross products
11b = 5c
Divide by 11
b = 5c/11
Now we want
2a = 7b
Substitute in 5c/11 for b
2a = 7(5c/11)
2a = 35c/11
Multiply by 11
2a*11 = 35c
22a = 35c
Divide by c
22 a/c = 35
Divide by 22
a/c = 35/22
a:c = 35:22
b:c = 14:3
Using cross products
3b = 14c
Divide by 3
b = 14c/3
Now we want
9a = 2b
Substitute in 14c/3 for b
9a = 2(14c/3)
9a = 28c/3
Multiply by 3
9a*3 = 28c
27a = 28c
Divide by c
27 a/c = 28
Divide by 27
a/c = 28/27
a:c = 28:27
Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
#SPJ4
