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IrinaVladis [17]

2 years ago

14

What is the equation of a line, in general form, with a point (-3, 0) and an undefined slope?

2 answers:

navik [9.2K]2 years ago

6 0

An undefined slope is a vertical line.

so if it passes through (-3, 0)

The equation will be ; x = -3.

irina1246 [14]2 years ago

3 0

Undefined slope...with a point (-3,0)

ok u need to learn this...
VUX -- vertical line, undefined slope, represented by x = the x in (x,y)
HOY -- horizontal line, 0 slope, represented by y = the y in (x,y)

so ur line would be : x = -3...but in general form, it is Ax + By + C = 0....so this equation would be x + 0y + 3 = 0...I think

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A triangle has coordinates A (1, 5), B (-2, 1) and C (0, -4). What are the new coordinates if the triangle is dilated with a sca

Brilliant_brown [7]

IF you are dilating about the origin, which you didn't exactly state, the new coordinates are A' (1/5, 1), B' (2/5, 1/5), C' (0, 4/5). Dilation is all about distance, so you have to move the new coordinates to whatever the scale factor is times the x and y distance. For example, A is at (1, 5), so 1/5 of 1 is 1/5, and 1/5 of 5 is 1, hence your new coordinate for A. It is a fifth of the distance from the origin as its preimage is.

8 0

2 years ago

- The circumference of a circle is 8 feet. What is the diameter of the circle?

Mariana [72]

Answer:

Step-by-step explanation:

4 0

2 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

A water tank in the shape of an inverted circular cone has a base radius of 3 m and height of 7 m . If water is being pumped int

Wittaler [7]

The water level increases by 0.608 meters per minute when the water is 3.5 m deep

<h3>How to determine the rate?</h3>

The given parameters are:

Radius, r = 3
Height, h = 7
Rate in, V' = 4.3m^3/min

The relationship between the radius and height is:

r/h = 3/7

Make r the subject

r = 3h/7

The volume of a cone is;

$V = \frac 13\pi r^2h$

This gives

$V = \frac 13\pi (\frac{3h}{7})^2h$

Expand

$V = \frac{3h^3}{49}\pi$

Differentiate

$V' = \frac{9h^2}{49}\pi h'$

Make h' the subject

$h' = \frac{49}{9\pi h^2}V'$

When the water level is 3.5.

We have:

$h' = \frac{49}{9\pi * 3.5^2}V'$

Also, we have:

V' = 4.3

So, the equation becomes

$h' = \frac{49}{9\pi * 3.5^2} * 4.3$

Evaluate the products

$h' = \frac{210.7}{346.36}$

Evaluate the quotient

h' = 0.608

Hence, the water level increases by 0.608 meters per minute

Read more about volumes at:

brainly.com/question/10373132

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7 0

1 year ago

Find the value of x in the below complementary angle 3x(5x+2)

Natali [406]

Answer:

The value of x is 11

Step-by-step explanation:

<em>Two angles are complementary if the sum of their measures is 90°</em>

Let us use this rule to solve our question

∵ The angle of measure (3x)° and the angle of measure (5x + 2)°

are complementary angles

→ That means their sum equals 90°

∴ 3x + 5x + 2 = 90

→ Add the like terms in the left side

∵ (3x + 5x) + 2 = 90

∴ 8x + 2 = 90

→ Subtract 2 from both sides to move 2 from the left side to the right side

∵ 8x + 2 - 2 = 90 - 2

∴ 8x = 88

→ Divide both sides by 8 to find x

∵ 8x/8 = 88/8

∴ x = 11

∴ The value of x is 11

7 0

2 years ago