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1 year ago

Is (7, -2) a solution to this system of equations? X - 5y = -3 y = -2 yes no

Mathematics

1 answer:

MatroZZZ [7]1 year ago

3 0

Answer:

No.

Step-by-step explanation:

Plug in -2 for y and 7 for x in the first equation:

x - 5y = -3

(7) - 5(-2) = -3

Simplify. Remember to follow PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& roots)

Multiplications

Divisions

Additions

Subtractions

First, multiply -5 with -2:

7 + (-5 * -2) = -3

7 + (10) = -3

Next, add:

7 + 10 = -3

17 ≠ -3

(7, -2) is not a solution for the given system of equations:

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A store owner has 7.41 lbs. of candy. If she puts the candy into 9 jars, how much candy will each jar contain with how much left

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Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140

Westkost [7]

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140 apples, went to market and sold all their apples at the same price, and each received the same sum of money.

Formula : $a \times n + (n - 1)$ , $(a + b)\cdot n + (n - 2)$ , $(a + 2 \cdot b) \cdot n + (n - 3)$ , $(a + 3 \cdot b) \cdot n + (n - 4)$ , $(a + 4 \cdot b) \cdot n + (n - 5)$ , $(a + 5 \cdot b) \cdot n + (n - 6)$ , $(a + 6 \cdot b) \cdot n + (n - 7)$

$a \cdot n + (n - 1) = 20$

$(a + b) \cdot n + (n - 2)=40$

$(a + 2 \cdot b) \cdot n + (n - 3) = 60$

$(a + 3 \cdot b) \cdot n + (n - 4) = 80$

$(a + 4 \cdot b) \cdot n + (n - 5) = 100$

$(a + 5 \cdot b) \cdot n + (n - 6) = 120$

$(a + 6 \cdot b) \cdot n + (n - 7) = 140$

On solving :

n = 7, a = 2, b = 3

So,

$2 \times 7 + 6 = 20$

$5 \times 7 + 5=40$

$8 \times 7 + 4 = 60$

$11 \times 7 + 3 = 80$

$14 \times 7 + 2 = 100$

$17 \times 7 + 1 = 120$

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 + 3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.

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