you have 4 fields where it can land, so the probability has a denominator 4.
2 of those fields have a even number so the numerator is 2.
-> probability is 2/4= 1/2
For this case as MNOP is a square then the angles of each vertex are equal to 90 degrees.
Therefore, we have the following equations:
![4t + 20 = 90\\7f + 6 = 90](https://tex.z-dn.net/?f=%204t%20%2B%2020%20%3D%2090%5C%5C7f%20%2B%206%20%3D%2090%20%20)
From these equations, we can clear the values of the unknowns.
For equation 1 we have:
![4t + 20 = 90\\4t = 90 - 20\\4t = 70](https://tex.z-dn.net/?f=%204t%20%2B%2020%20%3D%2090%5C%5C4t%20%3D%2090%20-%2020%5C%5C4t%20%3D%2070%20%20)
![t = \frac{70}{4}\\t = 17.5](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7B70%7D%7B4%7D%5C%5Ct%20%3D%2017.5%20%20%20)
For equation 2 we have:
![7f + 6 = 90\\7f = 90 - 6\\7f = 84](https://tex.z-dn.net/?f=%207f%20%2B%206%20%3D%2090%5C%5C7f%20%3D%2090%20-%206%5C%5C7f%20%3D%2084%20%20)
![f = \frac{84}{7}\\f = 12](https://tex.z-dn.net/?f=%20f%20%3D%20%5Cfrac%7B84%7D%7B7%7D%5C%5Cf%20%3D%2012%20%20%20)
Answer:
The values of t and f are given by:
![t = 17.5\\f = 12](https://tex.z-dn.net/?f=%20t%20%3D%2017.5%5C%5Cf%20%3D%2012%20)
Answer: 24 possible ways
A set of 4 tires can be fixed in any of the four possible positions in a car as it is mentioned that all four tires are interchangeable. Therefore, the 4 tires can be fixed in 4! ways. The four interchangeable tires can be put on a car in 24 possible ways.
Step-by-step explanation:
looked it up
Answer: hi
Step-by-step explanation:
hi