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serious [3.7K]
2 years ago
15

 Jamal works at a sporting goods store on the weekends. Suppose last weekend he worked

Mathematics
1 answer:
rusak2 [61]2 years ago
3 0

Answer:

$8.8 per hour

Step-by-step explanation:

Well, the equation is simple.

Time (hours) * Money (per hour) = Total

We know the time he worked for and the total amount he earned, so just replace in this equation and find the unknown number

12.5 * money = 110

To find the money he earns per hour we should just simply divide the total amount he earned by the hours he spent working

money = 110/12.5

money = 8.8$

You can also check it out to make sure it's correct.

If he earns 8.8$ per hour and worked for 12.5 hours how much he'll earn? Let's find out

8.8 * 12.5 =?

8.8 * 12.5 = 110, the same total amount so our solution must be correct.

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Select all the correct graphs.
Anika [276]

Answer:

garoph 1 and 2 hope this helps

Step-by-step explanation:

3 0
3 years ago
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The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
Liula [17]
I believe that would be -4.50 for problems like this you subtract then add the negative sign in front
i'm surprised you are in high school i did this in 6th grade
7 0
3 years ago
Use the function f(x) to answer the questions.
fiasKO [112]

Answer:

Below in bold.

Step-by-step explanation:

A. −16x2 + 24x + 16 = 0

-8(2x2 - 3x - 2) = 0

-8(2x + 1 )(x - 2) = 0

x = -0.5, 2.

So the x-intercepts are (-0/5, 0) and (2, 0).

B.  As the leading coefficients is negative (-16) the vertex of the graph will be a Maximum.

To find its coordinates we convert the function to vertex form:

f(x) =  −16x2 + 24x + 16

=  -16(x^2 - 1.5x) + 16

Completing the square on  contents of the parentheses:

= -16 [(x - 0.75)^2  - 0.75^2] + 16

= -16(x - 0.75)^2  - 16 * -0.75^2 + 16

= -16(x - 0.75)^2 + 9 + 16

= -16(x - 0.75)^2 + 25.

So the coordinates of the vertex are (0.75, 25)

3 0
2 years ago
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

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Yuri [45]
The answer is c i believe
4 0
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