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3 years ago

Someone help? Where do i drag which?

Mathematics

1 answer:

Elena-2011 [213]3 years ago

3 0

Answer:

matching them

1) e

2) l

3) k

4) n

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Can somebody help me please

irina1246 [14]

The correct answer is 67 to the third power

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3 years ago

Read 2 more answers

How do you simplify this expression with an answer in positive exponential notation? Please provide the process. Thank you!

Otrada [13]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\ -------------------------------\\\\ 8^{-2}\cdot \cfrac{3^0-8^{-3}}{4^{-5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{8^3}}{\frac{1}{4^5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{(2^3)^3}}{\frac{1}{(2^2)^5}}$

$\bf 8^{-2}\cdot \cfrac{\quad \frac{512-1}{2^9}\quad }{\frac{1}{2^{10}}}\implies (2^3)^{-2}\cdot \cfrac{\quad \frac{511}{2^9}\quad }{\frac{1}{2^{10}}}\implies 2^{-6}\cdot \cfrac{511}{2^9}\cdot \cfrac{2^{10}}{1} \\\\\\ 2^{-6}\cdot \cfrac{511\cdot 2^{10}}{2^9}\implies 2^{-6}\cdot 511\cdot 2^{10}\cdot 2^{-9}\implies 2^{-6}\cdot 511\cdot 2^{10-9} \\\\\\ 2^{-6}\cdot 511\cdot 2\implies 511\cdot 2^{-6}\cdot 2\implies 511\cdot 2^{-6+1}\implies 511\cdot 2^{-5} \\\\\\ 511\cdot \cfrac{1}{2^5}\implies \cfrac{511}{32}$

4 0

4 years ago

PLS HELP ME PLZZ!!!!!!!!!!!! =)

alina1380 [7]

81. a negative times a negative is a positive

8 0

3 years ago

For what value of a do the lines 5x–2y=3 and x+y=a intersect at a point on the y-axis?

Svetlanka [38]

So what they are trying to say is that they both have the same y-intercept. Easy!

Make y the subject:

5x - 2y = 3

2y = 5x - 3

y = 2.5x - 1.5

The y-intercept is -1.5.

Make y the subject:

x + y = a

y = -x + a

Therefore, a must be -1.5 !

6 0

4 years ago

CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION

vampirchik [111]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

A(1, 4 ) → A'(1, - 4 )

B(3, - 2 ) → B'(3, 2 )

C(4, 2 ) → C'(4, - 2 )

4 0

4 years ago