Flagella and cilia are both used for movement
Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Answer: all of them
Explanation: I think they’re all true
Hope this helps!
Answer:
200 approximate
Explanation:
depends how many in common
There are 4 significant figures