Gradient, m=
![\frac{change in y}{change in x}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bchange%20in%20y%7D%7Bchange%20in%20x%7D%20)
m=
![\frac{8-2}{-5--3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8-2%7D%7B-5--3%7D%20)
m=
![\frac{6}{-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B-2%7D%20)
m=-3
Equation;
y=mx+c
y=-3x+c
Using point (-3,2) to replace for x and y;
2=-3(-3)+c
2=9+c
c=-7
y=-3x-7
Answer:
You would most likely would want to use Pythagorean Theorem, witch is, a²+b²=c²
The correct answer would be C.)-3
First thing First. You must find have a common denominator. If you want to find it then you do this
3: 3 6 9 12 15 18 21
7: 7 14 21 28
Once you found a number they have in common (21) You do this next
3/7 * 3/3 = 9/21
2/3 * 7/7 = 14/21
Now the next thing you do is subtract your numerators but not the denominators
14-9=5
5/12
you cant simplified so your done! Hope this helps!!!! <span />
Check the picture below.
so, if we get the whole area of the figure, which will be the combined areas of those three rectangles, and if we get the area of the triangle, and then subtract that area from of the triangle from the whole figure's area, we're in effect making a whole in the total area, and what's leftover is the shaded area.
![\bf \stackrel{\textit{area of the rectangles}}{(1.6\cdot 5.2)+(2.7\cdot 8.4)+(1.6\cdot 5.2)}~~-~~\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(2.7)(8.4)} \\\\\\ 8.32+22.68+8.32~~-~~11.34\implies 39.32-11.34\implies 27.98](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20rectangles%7D%7D%7B%281.6%5Ccdot%205.2%29%2B%282.7%5Ccdot%208.4%29%2B%281.6%5Ccdot%205.2%29%7D~~-~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20triangle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%282.7%29%288.4%29%7D%20%5C%5C%5C%5C%5C%5C%208.32%2B22.68%2B8.32~~-~~11.34%5Cimplies%2039.32-11.34%5Cimplies%2027.98)