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Reptile [31]
3 years ago
6

The points N(-3,-3)(−3,−3), O(-3,-9)(−3,−9), and P(5,-3)(5,−3) form a triangle. Plot the points then click the "Graph Triangle"

button. Then find the perimeter of the triangle. Round your answer to the nearest tenth if necessary.
Mathematics
1 answer:
stich3 [128]3 years ago
8 0

Answer:

Perimeter = 30.42

Step-by-step explanation:

Using Distance Formula, √((x2-x1)^2 + (y2-y1)^2)

Find the Distance Between NO, OP, and NP

√((-3 - -3)^2 + (3 - 9)^2) - NO = 6

√((-3 - 5)^2 + (9 - -3)^2) - OP = 14.42

√((-3 - 5)^2 + (3 - -3)^2) - NP = 10

Sum All of Them = 10 + 6 + 14.42 = 30.42

You might be interested in
Prove that all integers from n to n+m is given by
ch4aika [34]

Answer:

no need to prove ,I believe you

Step-by-step explanation:

i believe you

6 0
3 years ago
A random sample of n measurements was selected from a population with unknown mean mu and standard deviation sigmaequals50 for e
Andre45 [30]

Answer:

a) (26.50;57.50)

b) (117.34;128.66)

c) (12.13;27.87)

d) (-4.73;11.01)

e) No. Since the sample sizes are large (n ≥ 30), the central limit theorem  guarantees that \bar x is approximately normal, so the confidence intervals are valid

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

And for a 95% of confidence the significance is given by \alpha=1-0.95=0.05, and \frac{\alpha}{2}=0.025. Since we know the population standard deviation we can calculate the critical value z_{0.025}= \pm 1.96

Part a

n=40,\bar X=42,\sigma=50

If we use the formula (1) and we replace the values we got:

42 - 1.96 \frac{50}{\sqrt{40}}=26.50  

42 + 1.96 \frac{50}{\sqrt{40}}=57.50  

The 95% confidence interval is given by (26.50;57.50)

Part b

n=300,\bar X=123,\sigma=50

If we use the formula (1) and we replace the values we got:

123 - 1.96 \frac{50}{\sqrt{300}}=117.34  

123 + 1.96 \frac{50}{\sqrt{300}}=128.66  

The 95% confidence interval is given by (117.34;128.66)

Part c

n=155,\bar X=20,\sigma=50

If we use the formula (1) and we replace the values we got:

20 - 1.96 \frac{50}{\sqrt{155}}=12.13  

20 + 1.96 \frac{50}{\sqrt{155}}=27.87  

The 95% confidence interval is given by (12.13;27.87)

Part d

n=155,\bar X=3.14,\sigma=50

If we use the formula (1) and we replace the values we got:

3.14 - 1.96 \frac{50}{\sqrt{155}}=-4.73  

3.14 + 1.96 \frac{50}{\sqrt{155}}=11.01  

The 95% confidence interval is given by (-4.73;11.01)

Part e

No. Since the sample sizes are large (n ≥ 30), the central limit theorem  guarantees that \bar x is approximately normal, so the confidence intervals are valid

8 0
3 years ago
There are 25 students that would like to go on a field trip, but only 18 may go. How many different combinations of students cou
Naya [18.7K]

480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.

The key to solve this problem is using the combination formula nC_{r}=\frac{n!}{r!(n-r)!}. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.

The total of students is n and the only that 18 students may go is r:

25C_{18}=\frac{25!}{18!(7!)}=480700

6 0
3 years ago
__ The average number of hourly visitors to an art exhibit is 45.13. Write the average number of hourly visitors as a mixed numb
77julia77 [94]

Answer:

45¹³/₁₀₀

Step-by-step explanation:

The average number of hourly visitors to an art exhibit is 45.13.

We are required to write the average number of hourly visitors as a mixed number.

45.13=45+0.13

0.13=13/100 in its simplest form.

Therefore:

45.13=45+13/100

Writing this as a mixed number, we have:

45.13= 45¹³/₁₀₀

Therefore the average number of hourly visitor is given by 45¹³/₁₀₀

7 0
4 years ago
A publisher estimates the annual demand for a book to be 8000 copies, and built a warehouse to accommodate at most 8000 copies.
Illusion [34]

Answer: $1000

Step-by-step explanation:

Annual demand (D) = 8000

Cost per order (S) = $1000

Cost per unit to print = $8 per book

Storage cost = $2 per book per year

The minimum total cost can be found thus :

√(2 × D × S) / storage cost * cost per unit

√(2 × 8000 × 1000) / (2 * 8)

√ (16,000,000 / 16

√ (1,000,000

= 1000

Hence , minimum total cost $1000

8 0
3 years ago
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