All categories

3 years ago

What is 2x+ 3x simplified ?

Mathematics

1 answer:

Amanda [17]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Which coordinate is on the graph of the equation 4x-3y=8

Wittaler [7]

Answer:

Coordinates (0, -8/3)

4 0

3 years ago

Find the area of the regular polygon.<br> Round to the nearest tenth.

Keith_Richards [23]

Answer: $\text{Area}=110.9 ft^2$

Step-by-step explanation:

The given regular polygon has 3 sides, therefore, it is a triangle with all sides equal and called equilateral triangle.

The area of equilateral triangle is given by:-

$\text{Area}=\frac{\sqrt{3}}{4}a^2$ , where a is the side length of equilateral triangle.

Now, the area of given equilateral triangle with sides = 16 ft. is given by:-

$\text{Area}=\frac{\sqrt{3}}{4}(16)^2\\\Rightarrow\text{Area}=\frac{\sqrt{3}}{4}(256)\\\Rightarrow\text{Area}=110.85\approx110.9 ft^2$

4 0

3 years ago

Lin created a design in his scrapbook by cutting square sheets of paper along the diagonal, as shown. Which equation can be used

WITCHER [35]

Answer:

the answer is A=(8)(8)/2

Step-by-step explanation:

4 0

3 years ago

Solve for n <br> 10n+0.3=0.1+0.3

galina1969 [7]

Answer:

0.01 is the awnser can you put me as the brainlest awnser

Step-by-step explanation:

4 0

3 years ago

Which expression is equivalent to StartFraction StartRoot 2 EndRoot Over RootIndex 3 StartRoot 2 EndRoot EndFraction? One-fourth

Talja [164]

Question:

Which expression is equivalent to

$\frac{\sqrt{2}}{\sqrt[3]{2}}$

Answer:

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}$

Step-by-step explanation:

Given

$\frac{\sqrt{2}}{\sqrt[3]{2}}$

Required

Simplify

From laws of indices;

$\sqrt[n]{x} =x^{\frac{1}{n}}$

So, the expression can be rewritten as

$\frac{\sqrt{2}}{\sqrt[3]{2}} = \frac{{2^{\frac{1}{2}}}}{2^{\frac{1}{3}}}$

Also, from laws of indices

$\frac{x^a}{x^b} = x^{a-b}$

So, the expression is further solved to:

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{2} - \frac{1}{3}$

Solve exponents as fraction

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{3-2}{6}}$

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}}$

This can be rewritten as

$\frac{\sqrt{2}}{\sqrt[3]{2}} =2^{\frac{1}{6}} = \sqrt[6]{2}$

5 0

3 years ago

Read 2 more answers