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2 years ago

13

Which pair of angles are alternate exterior angles of parallel lines v and w?

1 answer:

vampirchik [111]2 years ago

8 0

Answer:

a and d

Step-by-step explanation:

v and w are parallel lines

R is the transversal

Alternate exterior means on the opposite sides of the transversal and outside of the parallel linea

a and d are alternate exterior angles

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How many terms are in the expression?<br><br> 4x + 3y + 7z + 5<br><br> I need help ASAP!

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4.

Step-by-step explanation:

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3 years ago

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Find the measurement of KL (round your answer to the nearest one hundredth. Which theorem did you use?

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0f the 64 students in grade five, 3/8 of them either walk or ride a bike to school. The rest take a bus. How many fifth graders

UkoKoshka [18]

40 fifth graders take a bus to school. 8x8= 64 so they have you a good fraction to start with to find out how many kids are walking or taking their bike (3/8) all you have to do is multiply 3 and 8 which equals 24 to find the fraction of the amount of kids who take the bus you subtract 3 from 8 which gives 5/8 and to get the answer you multiply 5 and 8 which is 40.

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3 years ago

"Complete the square" to convert the equation of each circle to graphing form. Identify the center and the radius.

Reil [10]

Answer:

The center is (-3,2) and the radius is r=2

Step-by-step explanation:

The general equation of the given circle is

$x^2+6x+y^2-4y=-9$

Add the square of half the coefficient of the linear terms to both sides of the equation to obtain;

$x^2+6x+3^2+y^2-4y+(-2)^2=-9+3^2+(-2)^2$

$x^2+6x+9+y^2-4y+4=-9+9+4$

$x^2+6x+9+y^2-4y+4=4$

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We factor to obtain;

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$(x--3)^2+(y-2)^2=2^2$

Comparing to:

$(x-h)^2+(y-k)^2=r^2$

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8 0

3 years ago

Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different

IgorC [24]

Answer:

$20$

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players $=6$

total teams to be formed $=2$

total players in one team $=3$

we have to number of ways of selecting $3$ players for one team, rest $3$ will go in other team.

Total number of ways of selecting $3$ players $=^6C_3$

$=\frac{6!}{3!3!}$

$=20$

Hence total number of different ways in which they can be put into two different teams is $6$

5 0

4 years ago