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denpristay [2]
3 years ago
6

PLEASE HELP WITH THIS MATH QUESTION

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
Table C is a function because there is one x-value for every y-value.
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An architect is creating a scale drawing of a school computer lab. The length of the lab is 32 feet and the width of the lab is
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The scale drawing of the computer lab will have a length of 4 centimeter and a widtgh of 6 centimeter.
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Dingane has \$8.00$8.00dollar sign, 8, point, 00, and exactly 30\%30%30, percent of that money is from 555‑cent coins. How many
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<span>If Dingane has $8.00, and thirty percent of that money is from five cent coins, then 8 x 0.3 = $2.40 of Dingane's money is made of five cent coins. In this case the number of five cent coins is the number of cents divided by five: 240/5 = 48. Therefore, Dingane has forty-eight five-cent coins.</span>
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3 years ago
How many different values can an algebraic expression like 5+(x+2)
elena-14-01-66 [18.8K]

wb. lnehiu gliaghjnkmnafvgsbhdnjfnmydabgshdnjmfkg

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3 years ago
How do you solve thsi
VLD [36.1K]
You multiply the length of the model car by the meters from the actual car. It’s easier to convert one unit of measurement to match with the other. I found it easier to convert 18.2 cm to meters which is 0.182 m. Now we multiply 0.182m by 0.3m to get the length of the actual car.

The answer would be 0.0546m. Or if you prefer centimeters, then the answer would be 5.46 cm. Either way is fine.

Hope this helped, please let me know if I was correct. :D
5 0
3 years ago
An athletic facility is building an indoor track. The track is composed of a rectangle and two semicircles.
Mazyrski [523]

Answer:

(The image is not provided, so i draw an idea of how i supposed that the problem is, the image is at the bottom)

Ok, we have a rectangle of length x by r.

At the extremes of length r, we add two semicircles.

So the perimeter will be equal to:

Two times x, plus the perimeter of the two semicircles (that can be thought as only one circle).

The radius of the semicircles is r, and the perimeter of a circle is:

C = 2*pi*r

where pi = 3.14

Then the perimeter of the track is:

P = 2*x + 2*pi*r.

b) now we want to solve this for x, this means isolating x in one side of the equation.

P - 2*pi*r = 2*x

P/2 - pi*r = x.

c) now we have:

P = 660ft

r = 50ft

then we can replace the values and find x.

x = 660ft/2 - 3.14*50ft = 173ft

5 0
3 years ago
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