Answer:
25 Paper Clips
Step-by-step explanation:
100cm is equal to 1 meter. So to find the answer you would need to take the whole of the centimeter (100) and divide that by the paper clips length (4).
100/4 = 25
So, to form a straight line 10 meters long you would need 25 paper clips each 4cm long.
All points that lie in a given line with a defined equation, they satisfy the equation such that when the values of x and y are substituted they satisfy the given equation.
Substituting values of y and x in the equation y = 14x +4
(8,6), (-8,-5), (-16,0), (-20,1) doesn't satisfy the equation.
therefore in this case there is no point that would lie in the line
<span>The product of a constant factor of six and a factor with the sum of two terms, because 6* the sum of y+3.
</span>
The total angle sum of a triangle is 180°
As such, 180= 78 + 2s +4s
102= 6s
s=17
Answer:
The current temperature on the X scale is 1150 °X.
Step-by-step explanation:
Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:



The difference between current temperature in Y linear scale with respect to freezing point is:


The change in X linear scale is:



Lastly, the current temperature on the X scale is:


The current temperature on the X scale is 1150 °X.