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arsen [322]
2 years ago
13

How are algebraic expressions used to represent and solve problem

Mathematics
1 answer:
spin [16.1K]2 years ago
8 0

The purpose of solving an algebraic expression in an equation is to find the unknown variable. When two expressions are equated, they form an equation and therefore, it becomes easier to solve for the unknown terms. To solve an equation, place the variables on one side and the constants on the other side.

Sure hope this helps

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Sylvie needs $110 for a concert ticket. She already has $16 and she can earn the rest by working 10 hours at her job. If h repre
oksano4ka [1.4K]

Answer:9.4$ a hour

Step-by-step explanation:

110 - 16 = 94

94 / 10 = 9.4

she makes 9.4$ a hour

<!> Brainliest is appreciated! <!>

6 0
2 years ago
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Which of the following equations could represebt the point in the table select all the following
r-ruslan [8.4K]

Answer:

what are the equations

Step-by-step explanation:

you didnt show the equations

6 0
2 years ago
What is the solution of 2p-14=4(p+5)
Pavel [41]
2p-14=4(p+5) Step 1, parentheses 2p-14=4p+20 Subtract 20 from each side of the equation 2p-34=4p Subtract 2p from each side -34=2p Divide each side by 2 -17=p
8 0
3 years ago
Which intervals show f(x) decreasing? Check all that apply.
wolverine [178]

The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

<h3>Which intervals naming the answer choices show the function f(x) decreasing?</h3>

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]

Read more on decreasing intervals;

brainly.com/question/1503051

#SPJ1

4 0
2 years ago
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
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