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Lisa [10]
3 years ago
12

8. If ASDE – ASWT, find WT. D 5x + 3 56 S 40 7

Mathematics
1 answer:
disa [49]3 years ago
3 0
5+ 3 Well a times it would probably be 40
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Find the value of x. round to the nearest tenth.
valkas [14]

Answer:

Step-by-step explanation:

21.7

Use the cosine function, which is the ratio (adjacent side) / (hypotenuse).

Here we have cos 37 degrees = adj / hyp = 17.3 / x, and so

 x            1        

------ = -------------------

17.3       cos 37 deg

Then the hypotenuse length, x, is 17.3 / 0.799 = 21.7

5 0
3 years ago
The balance in Petra's account is -$32.50. The balance in John's
Firlakuza [10]

Answer:

Petra

Step-by-step explanation:

Petra's acc has $32.50,while John's balance acc has $34.60 so,petra has less balance money

7 0
3 years ago
Help please quick!!!
mina [271]

Answer:

just multiply two numbers on the rombus and you have your answer

5 0
3 years ago
A box contains 6 plain pencils and 2 pens. A second box contains 3 color pencils and 5 crayons. One item from each box is chosen
yKpoI14uk [10]

Answer: The probability of picking a pen from the first box and a crayon from the second box is 5/8 x 1/4 = 5/32.

Step-by-step explanation:

What is the probability of choosing a pen from the first box? It is 5/8.

 

What is the probability of selecting a crayon from the second box? It is 3/12 = 1/4.

The probability of picking a pen from the first box and a crayon from the second box is 5/8 x 1/4 = 5/32.

5 0
3 years ago
If the point (x, y) is on the small rectangle, then which point must be on the large rectangle?
ANTONII [103]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. This question is incomplete but I'm going to help you assuming some things:

  • The small rectangle is built up by the x and y-axis and the point (x,y)=(6,4)

  • The large rectangle is built up by the x and y-axis and the point that follows the rule:

(x',y')\rightarrow (x+4,y+4)

For the small rectangle, the vertices are:

A(0,0) \\ \\ B(6,0) \\ \\ C(6,4) \\ \\ D(0,4)

Therefore, if (6,4) lies on the small rectangle, for the large rectangle we have:

(x',y')=(6+4,4+4)=(10,4)

In conclusion:

If point (6,6) lies on the small rectangle, then (10,4) lies on the large rectangle.

6 0
3 years ago
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