Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
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The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Answer:
472 3/4
Step-by-step explanation:
Consider the meaning of "one, and one more". That does not mean zero (1-1). Rather, it means two (1+1).
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Then 3/4 and 472 more is ...

Eric has 472 3/4 buckets filled with sand.
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The problem statement here seems to be focused on the filled buckets, rather than the sand stockpile that Eric is working from. The amount in that stockpile is being reduced by the amount that is being used to fill buckets. In short, whether you add or subtract depends on what you're trying to figure.
7/6x=140
since variable x is multiplied by 7/6, find x by multiplying by the inverse of 7/6 which is 6/7.
7/6x × 6/7 = 140 × 6/7
x= 120