Answer:
A baseball player hit 73 home runs in a season.
Of the 73 home runs, 25 went to right field, 25 went to right center field, 8 went to center field, 10 went to left center field, and 5 went to left field.
(a) the probability that a randomly selected home run was hit to left center field =
= 13.69%
(B) Since the probability of an unusual event is 0, it was possible for this player to hit a home run to left center field.
B is the correct answer
hope this helps
Answer:
197
Step-by-step explanation:
Divide 1640 by 25
1640/25=65
Then multiply 65 and 3
65x3=197