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2 years ago

Can you help me find the answer quick

Mathematics

2 answers:

stepan [7]2 years ago

6 0

Answer:

Step-by-step explanation:

The answer is 14x + 30y - 20.

Before listing the steps, I am gonna list the vocabularies that might be helpful to understand the question.

Coefficient: A number by which another number or symbol is multiplied.

Ex: 5 is the coefficient of y in the term 5y.

Variable: A quantity that can have any one of a set of values or a symbol that represents such a quantity.

Ex: y is the variable of 5 in the term of 5y

Constant: A value that does not change.

Ex: 20 is the constant in 5y + 20

Step 1: After distributing the 14, we will have 14x + 14y + y - 20 + 15y

Step 2: Now, we are going to combine like terms. If you are getting confused, you can start with x and look for other xs in the equation that might be there to combine. After doing x, you can do y. Look for other ys in the equation to combine. After combining all, we will have 14x + 30y - 20.

I hope this was helpful. Let me know if you need any clarification or further help.

Nimfa-mama [501]2 years ago

3 0

Answer:

14x+30y-20

Step-by-step explanation:

14(x+y)=14x+14y

14y+y=15y+15y=30y

and there is no like terms for -20 and 14x so the answer is

14x+30y-20

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Answer:

The future value of this initial investment after the six year period is $2611.6552

Step-by-step explanation:

Consider the provided information.

A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.

Future value of an investment: $FV=P(1+r)^n$

Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.

9% compounded semiannually for 6 years.

Therefore, the value of r is: $r=\frac{0.09}{2}=0.045$

Number of periods are: 2 × 6 = 12

Now substitute the respective values in the above formula.

$FV=1540(1+0.045)^{12}$

$FV=1540(1.045)^{12}$

$FV=1540(1.69588)$

$FV=2611.6552$

Hence, the future value of this initial investment after the six year period is $2611.6552

6 0

3 years ago

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Vadim26 [7]

Option B: FECBAD is the Hamilton path

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Given that ABCDEF is a graph with vertices A,B,C,D,E and F

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Since, we know that a Hamilton path is a path that touches every vertex in a graph exactly once.

Option A: EFADECBA

The path touches the vertices E and A twice.

Hence, the path EFADECBA is not a Hamilton path.

Therefore, Option A is not the correct answer.

Option B: FECBAD

The path touches every vertex in the graph exactly once.

Hence, the path FECBAD is a Hamilton path.

Therefore, Option B is the correct answer.

Option C: ADEFBD

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Hence, the path ADEFBD is not a Hamilton path.

Therefore, Option C is not the correct answer.

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The path touches the vertices E and A twice.

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Therefore, Option D is not the correct answer.

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Answer:

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