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Schach [20]
2 years ago
8

Find the measures of x and y. (Please answer correctly, with steps on how you got your answer as well please)

Mathematics
1 answer:
puteri [66]2 years ago
8 0

Answer:

x= 65 º

y= 25 º

Step-by-step explanation:

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14-7 = 7
7 more red roses than pink roses
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When I use 14 cat lovers to pet 350 cats, it takes 15 days. How long would it take to pet 480 cats if I use 18 cat lovers?
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I think it would take 16 days

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If the sin 60 degrees is 3/2, then the cos ______ degrees = ______.
PSYCHO15rus [73]

Answer: If the sin 60 degrees is 3/2, then the cost is 22 degrees and equals a bunch of like 88 degrees

Step-by-step explanation:

7 0
3 years ago
Why is it important to calculate the distance between two points on a cartesian coordinate plane?
Gwar [14]

Answer:

Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem,

a

2

+

b

2

=

c

2

, is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse. The relationship of sides

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

to side d is the same as that of sides a and b to side c. We use the absolute value symbol to indicate that the length is a positive number because the absolute value of any number is positive. (For example,

|

−

3

|

=

3

. ) The symbols

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

indicate that the lengths of the sides of the triangle are positive. To find the length c, take the square root of both sides of the Pythagorean Theorem.

c

2

=

a

2

+

b

2

→

c

=

√

a

2

+

b

2

It follows that the distance formula is given as

d

2

=

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

→

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

We do not have to use the absolute value symbols in this definition because any number squared is positive.

A GENERAL NOTE: THE DISTANCE FORMULA

Given endpoints

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

, the distance between two points is given by

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Step-by-step explanation:

4 0
3 years ago
Simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BX-10%7D" id="TexFormula1" title="\frac{1}{X-10}" alt="\frac{1}{X-10}
mr Goodwill [35]

In the second fraction, factorize the denominator:

x^2-9x-10=(x-10)(x+1)

Then we have, as long as x\neq10,

\dfrac1{x-10}\div\dfrac{9x}{x^2-9x-10}=\dfrac{\frac1{x-10}}{\frac{9x}{(x-10)(x+1)}}=\dfrac1{\frac{9x}{x+1}}=\dfrac{x+1}{9x}

which you could also write as

\dfrac{x+1}{9x}=\dfrac x{9x}+\dfrac1{9x}=\dfrac19+\dfrac1{9x}

4 0
2 years ago
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