Question

Bruce collects the data on four electric circuits listed in the table.

Answer 1

Answer : X and Z

Explanation :

For w :

Voltage, $V=18\ V$

resistance, $R=38\ \Omega$

so, $V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{18\ V}{38\ \Omega}$

$I=0.47$

$q=0.47\times8$

So charge,$q=It$

$q=3.76\ C$

For x :

Voltage, $V=24\ V$

resistance, $R=34\ \Omega$

so, $V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{24\ V}{34\ \Omega}$

$I=0.705$

$q=0.705\times8$

So charge,$q=It$

$q=5.64\ C$

For y :

Voltage, $V=34\ V$

resistance, $R=70\ \Omega$

so, $V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{34\ V}{70\ \Omega}$

$I=0.485$

$q=0.485\times8$

So charge,$q=It$

$q=3.88\ C$

For z :

Voltage, $V=12\ V$

resistance, $R=18\ \Omega$

so, $V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{12\ V}{18\ \Omega}$

$I=0.66$

$q=0.66\times8$

So charge,$q=It$

$q=5.28\ C$

So, the circuits X and Z delivers 5.64 C and 5.28 C of charge.

Hence, Bruce must include X and Z in his report.

Answer 2

X AND Z because tats what i got when i answered from edgeunity

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