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Vlad [161]
3 years ago
8

If a spear is jabbeb exactly at that place where the fish appears in water, the fish is not killed

Physics
1 answer:
Korvikt [17]3 years ago
7 0

You have learned your lesson well, Suhay. Your statement is correct.

The light rays from the fish BEND when they flow out of the water into the air. But our primitive brain still believes that the light rays flow STRAIGHT from the fish. The result is that the fish does not APPEAR to be at that place where it really is.

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Two protons are released from rest, one from location 1 and another from location 2. When these two protons reach location 3, th
BaLLatris [955]

Answer:

76.66V

Explanation:

Accorging to law of conservation of energy:

\Delta E=0\\E_f=E_i\\K_f+U_f=K_i+U_i}

Since the protons are released from rest, the initial kinetic energy is zero and the electric potencial energy is given by: U=qV

Now from U_f-U_i=-K_f, we have:

U_3-U_1=-K_1\\q(V_3-V_1)=-\frac{mv_1^2}{2}\\U_3-U_2=-K_2\\q(V_3-V_2)=-\frac{mv_2^2}{2}\\

Recall that v_1=2v_2, replacing:

q(V_3-V_1)=-\frac{m(2v_2)^2}{2}\\q(V_3-V_1)=-\frac{4mv_2^2}{2}\\q(V_3-V_1)=-4K_2(1)\\q(V_3-V_2)=-K_2(2)

Rewriting (1) for -K_2:

q(V_3-V_1)=-4K_2\\-K_2=\frac{q(V_3-V_1)}{4}(3)\\

Now, equaling (2) and (3):

q(V_3-V_2)=\frac{q(V_3-V_1)}{4}

Finally, rewriting for V_3

(V_3-V_2)=\frac{V_3-V_1}{4}\\4V_3-4V_2-V_3=-V_1\\3V_3=4V_2-V_1\\V_3=\frac{4V_2-V_1}{3}\\V_3=\frac{4(115V)-231V}{3}\\V_3=76.66V

6 0
3 years ago
A force platform is a tool used to analyze the performance of athletes measuring the vertical force that the athlete exerts on t
Phoenix [80]

Answer:

a.I=981.34 N*s

b.v_f=3.96 m/s

c.v_{f1}=3.63m/s

d.y_f=0.673m

Explanation:

Given: m=67kg, h=0.720m, 0

a.

I=\int\limits^{t_1}_{t_2} {F(t)} \, dt

F(t)=9200*t-11500t^2

I=\int\limits^{0.8s}_{0s}{9200*t-11500*t^2} \, dt

I=4600*t^2-3833.3*t^3|(0.80,0)

I=2944-1962.66=981.35

I=981.34 N*s

b.

v_f^2=v_i^2+a*y'

Starting from the rest

v_f^2=0+2*9.8m/s^2*0.80s

v_f^2=15.68

v_f=\sqrt{15.68m^2/s^2}=3.96 m/s

c.

I_{total}=p_f

I_1-m*g*d=m*v_{f1}-m*v_f

981.34-67kg*9.8m/s^2*0.720=67.0kg*v_{f1}-67.0kg*(-3.96m/s)

Solve to vf

v_{f1}=3.63m/s

d.

v_f^2=v_i^2+2*a*y_f'

y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2

y_f=0.673m

7 0
3 years ago
The shortest wavelengths that we can see are experienced as
max2010maxim [7]
The shortest wavelengths that you can see are experienced
as violet light, or whatever is the last color you can see on the
"blue end" of the spectrum.  It's not exactly the same for all eyes.
4 0
3 years ago
How wide in m is a single slit that produces its first minimum for 631-nm light at an angle of 12. 0°? m
kiruha [24]

The single slit  is 3.34 * 10^{-5} m wide .

In the single-slit diffraction experiment, we can observe the bending phenomenon of light or diffraction that causes light from a coherent source to interfere with itself and produce a distinctive pattern on the screen called the diffraction pattern.

Diffraction is evident when the sources are small enough that they are relatively the size of the wavelength of light.

Fringe width is defined as the distance between any two consecutive bright or dark fringes.

Using the formula ,

nλ = a sin θ

a = nλ /sin θ

a  = (1) (631 *10^{-9} ) / sin (12)

a = 3.34 * 10^{-5} m

Learn more about single-slit diffraction here:

brainly.com/question/14914432

#SPJ4

8 0
1 year ago
The motion analysis derived for use within a translating reference frame is not capable of including motion of the point occurri
Natali [406]

Answer:

False

Explanation:

The motion analysis that is derived to be used within a translating reference frame is capable of including the motion of a point that occurs within the translation  or we say in the translating frame because of the fact that for inertial frame, any motion can be implemented in translating frame provided that the frame is strictly inertial frame

5 0
3 years ago
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