Answer:
the red at the bottom should not count, but the red at the top is the least dense because it floats upon the other liquids
Explanation:
hope this helps
T = 3.5 secs
Velocity (v) = g * t = 10 m/s^2 * 3.5 sec = 35 m/s
I think D x=vxt because it's equation finding change of x (displacement) and using time
B) <span>Scientific study of matter and how materials interact with each other at the atomic level
b/c chem has to do with atoms
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The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
The given parameters;
- speed of the wildebeest calf, Vw = 10 m/s
- distance traveled by the calf before the cheetah stands up = 7 m
- constant acceleration of the cheetah, a = 9.5 m/s²
Let the speed of the cheetah = Vc
let the time the cheetah catches up with the wildebeest = t
Apply relative velocity formula to determine the time when the cheetah catches up with the widebeest;
Assuming the wildebeest and the cheetah are running in the same direction;
The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero;
Thus, if the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
Lear more here: brainly.com/question/24430414