Ask question

Ask question

All categories

2 years ago

5

Kirsten is making lanyards for a convention. She needs to make 1000 lanyards and knows that 1 lanyards uses 1.75 feet cord. How

much cord will Kirsten need

2 answers:

Tema [17]2 years ago

5 0

She will need 1,750 feet of cord.

professor190 [17]2 years ago

5 0

Its 1000 x 1.75 = 1750 feet of cord. She didnt need to do anything else. Just multiply.

You might be interested in

Match the given angle pair to their relationship using the figure beloe

hoa [83]

Answer:

Vertical: 1

corresponding: 3

alternate interior: 2

alternate exterior: 4

6 0

2 years ago

Which measure is less than 435 inches?

Alex_Xolod [135]

435 inches = 36 1/4 ft.

So, the answer would be D) 12 ft. 3 in.

*Hope I helped :)*

7 0

2 years ago

Recall the chapter example which described the fact that the mean IQ in large, diverse populations is 100 and the standard devia

vova2212 [387]

Answer:

The margin of error for the 99% confidence level for this sample is ±2.23.

None of the given figures is close to the answer:

E. None of the above

Step-by-step explanation:

margin of error (ME) around the mean can be calculated using the formula

ME= $\frac{z*s}{\sqrt{N} }$ where

z is the corresponding statistic of the 99% confidence level (2.576)

s is the population IQ standard deviation (15)

N is the sample size (300)

Using these numbers we get:

ME= $\frac{2.576*15}{\sqrt{300} }$ ≈ 2.23

7 0

2 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

2 years ago

At an electronics store, a $165 television is marked up 110%. Dave purchases the TV and must pay 6.5% sales tax. What is his fin

Mariana [72]

Firstly, we need to know the price of the TV after the 110$ increase.
$165 x 1.10 = $181.50
[This is an increase of $16.50]
[1.10 is the equivalent of 110%. 1 being 100% and the .10 being 10%]

Now for the sales tax. We apply a similar method.
$181.50 x 0.065 = $11.79
6.5% of $181.50 is $11.79, so we add the two together to find the final cost.

The final cost of the TV is $193.29

4 0

3 years ago