19/3 - 31/7.....LCD = 21
133/21 - 93/21 =
40/21 =
1 19/21 lbs.....closest answer is B...it is about 2 lbs
Answer:
½ sec²(x) + ln(|cos(x)|) + C
Step-by-step explanation:
∫ tan³(x) dx
∫ tan²(x) tan(x) dx
∫ (sec²(x) − 1) tan(x) dx
∫ (sec²(x) tan(x) − tan(x)) dx
∫ sec²(x) tan(x) dx − ∫ tan(x) dx
For the first integral, if u = sec(x), then du = sec(x) tan(x) dx.
∫ u du = ½ u² + C
Substituting back:
½ sec²(x) + C
For the second integral, tan(x) = sin(x) / cos(x). If u = cos(x), then du = -sin(x) dx.
∫ -du / u = -ln(u) + C
Substituting back:
-ln(|cos(x)|) + C
Therefore, the total integral is:
½ sec²(x) + ln(|cos(x)|) + C
Answer: first picture is for y=-5/3x + 3
Step-by-step explanation:
Answer:
4 and 12
Step-by-step explanation:
a = young
b = old
b = 3a, a+b =2a+8 => a = 4, b = 12
The answer is 16 brainly would help ;)
