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mestny [16]
4 years ago
15

50r − 6 = 82r − 70. a. r=64 b. r= -64 c.r=2 d.r=-2

Mathematics
1 answer:
lisabon 2012 [21]4 years ago
3 0

Answer:

c

Step-by-step explanation:

Hope this helps.

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A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening
lara [203]

Answer:

Step-by-step explanation:

Because of the nature of the information we are given, we have no choice but to use the equation

y=a(x-h)^2+k

and solve for a.

We know by the info that the vertex is (0, 84). We also know that if the vertex is at the origin, and that the base is 42 feet wide, it spans 21 feet to the right of the origin and 21 feet to the left of the origin. That means that we have 2 coordinates from which we need to pick one for our x and y in the equation. I don't like negatives, so I am going to choose the coordinate (21, 0) as x and y. Because this parabola opens upside down, as archways of door openings do, our "a" value better come out algebraically as a negative. Let's see...From the vertex we have that h = 0 and k = 84. So filling in:

0=a(21-0)^2+84 and simplifying a bit:

0 = 441a + 84 and

-84 = 441a so

a=-\frac{84}{441}=-\frac{4}{21} Good, a is negative. Your equation is, then:

y=-\frac{4}{21}x^2+84

3 0
3 years ago
Read 2 more answers
3/4 of x if x= 15/28<br> PLS HELP!!!!!!!
vfiekz [6]

Answer:

5/7

Step-by-step explanation:

first of mean to divide

so it really saying x ÷ 3/4 and x = 15/28

15/28 ÷ 3/4 but you cant divide fractions

so we use copy dote flip

copy 15/28

dote ×

flip 4/3

15/28 × 4/3

then cross simplafiy so 4 can go into 28, 7 rimes. and 3 can go into 15, 5 times

5/7

6 0
3 years ago
Read 2 more answers
Out of 1200 students of a school only 85% passed. how many students failed?​
DerKrebs [107]

Answer:15

Step-by-step explanation:

If 85% pass then 15% failed and 15% of 1,200 is 180 so 180 people failed.

7 0
3 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
4 years ago
Whats the average between 95 and 128
Leona [35]

Answer:

Below!

Step-by-step explanation:

111.5

3 0
3 years ago
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