Me to I was doing the work but just lost it I will try again
Answer:
Option 1 is the correct fraction as a division problem
<span>Simplifying
4(y + -3) = 6(y + 2)
Reorder the terms:
4(-3 + y) = 6(y + 2)
(-3 * 4 + y * 4) = 6(y + 2)
(-12 + 4y) = 6(y + 2)
Reorder the terms:
-12 + 4y = 6(2 + y)
-12 + 4y = (2 * 6 + y * 6)
-12 + 4y = (12 + 6y)
Solving
-12 + 4y = 12 + 6y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-6y' to each side of the equation.
-12 + 4y + -6y = 12 + 6y + -6y
Combine like terms: 4y + -6y = -2y
-12 + -2y = 12 + 6y + -6y
Combine like terms: 6y + -6y = 0
-12 + -2y = 12 + 0
-12 + -2y = 12
Add '12' to each side of the equation.
-12 + 12 + -2y = 12 + 12
Combine like terms: -12 + 12 = 0
0 + -2y = 12 + 12
-2y = 12 + 12
Combine like terms: 12 + 12 = 24
-2y = 24
Divide each side by '-2'.
y = -12
Simplifying
y = -12</span>
Answer:
It's heavy cream
Step-by-step explanation:
Homogenized milk has a density of 1.032 kg/L and
heavy cream has a density of 1.005 kg/L at 10°C.
At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms
To determine which container hold homogenized milk or heavy cream and How I know?
We findo the density of the measurements given and whatever it correspond to is what it is
First mass is 8.04kg
Liquid contained is 8 litres
SInce the density is kg/L
No need for conversion
Density = mass/volume = 8.04/8= 1.005kg/L
Heavy cream has a density of 1.005 kg/L at 10°C.
Therefore it correspond
