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Serhud [2]
3 years ago
13

what happens to 5/x + 5 as x decreases from a large positive number to a small positive number? does it increase, decrease, or s

tay the same?
Mathematics
2 answers:
nexus9112 [7]3 years ago
7 0
It will increase hope im right
bulgar [2K]3 years ago
5 0

Answer:

Increases

Step-by-step explanation:

It increases because, the greater the value of x the smaller the fraction is. If x was 25 the fraction would be 5/25 this makes the value of the equation 5.2. Now if x was a smaller positive number like 5. Then the fraction would be 5/5 which would cause the equation to be equal to 6.

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Please Help!
Bingel [31]
The tank is NOT filled with 8314.5 L of a liquid. I guess you meant <span>The tank is completely filled with 8314.5 grams of liquid." </span>
<span>(8314.5 g) / (230 L) = 36.15 g/L . Hope this helps!</span>
3 0
3 years ago
I need help<br> please someone
mina [271]

Answer:

second option

Step-by-step explanation:

x - y= 28

x+y = 56

4 0
2 years ago
Marking as brainyest PLEASE HELP
trasher [3.6K]

Answer:

C) f(x) increases by 900%

Step-by-step explanation:

The rate of change is

f(4) - f(3)

---------------

4-3

f(4) = 9*4 = 36

f(3) = 9*3 = 27

36 -27

---------------

4-3

9

-----

1

The rate of change is 9

To change to a percent, multiply by 100%

9*100% = 900%

5 0
3 years ago
Read 2 more answers
A little help here? <br><br><br> Whats the value of X?
zubka84 [21]
You’d add 65+79 to get 144 then subtract that from 180 and get 36 so X would be 36 :) hope this helped!
4 0
3 years ago
Read 2 more answers
The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.
djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

where,

r_1 = radius of sphere = \frac{Diamtere}{2}=\frac{8cm}{2}=4cm

r_2 = radius of cylindrical wire = \frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

\frac{4}{3}\pi r_1^3=\pi r_2^2h

\frac{4}{3}\times r_1^3=r_2^2h

\frac{4}{3}\times (4)^3=(0.1)^2h

h=8533.33cm\approx 8533cm

Therefore, the length of the wire is, 8533 cm

6 0
3 years ago
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