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s2008m [1.1K]
2 years ago
5

What is the equation of a line passing through the points (-3, -2) and (2, 0)?

Mathematics
1 answer:
Lostsunrise [7]2 years ago
7 0

Answer:

y=0.400x+-0.800

Step-by-step explanation:

Given the following question:

point A = (-3, -2)
point B = (2, 0)

To write the equation of the line that passes through two points we have to write the points in slope intercept form.

Formula for slope intercept:

y=mx+b

M is equal to the slope of the two points, so first we need to fine the slope of the two points.

(-3,-2)=(x1,y1)
(2,0)=(x2,y2)

m=\frac{y2-y1}{x2-x1}
m=\frac{0--2}{2--3} =\frac{2}{5}
m=\frac{2}{5} =0.400

y=mx+b
y=-2
m=0.400
x=-3
-2=0.400(-3)+b
0.400\times-3=-1.20
-2+1.2=-0.800
b=-0.800

y=0.400x+-0.800

Hope this helps.

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════════ ∘◦❁◦∘ ════════

<h3>Answer : y = ⅚x - 3</h3>

════════════════════

<h3>Known</h3>

x1 = 6

y1 = 2

x2 = (-6)

y2 = (-8)

════════════════════

<h3>Question</h3>

Equation of the line (y = mx + c)

════════════════════

<h3>Way to do</h3>

#First, you find the gradient (m)

m =  \frac{y2 - y1}{x2 - x1}  =  \frac{(( - 8) - 2)}{(( - 6) - 6)}  =  \frac{( - 10)}{( - 12)}  =  \frac{5}{6}

#Now use the formula of equation of the line

y - y1 = m(x - x1)

y - 2 = ⅚(x - 6)

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════════════════════

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