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I am Lyosha [343]
2 years ago
7

A hardware store orders at most $2,500 worth of concrete and sand. The store needs to make a profit of at least $2,750 on the or

der. The possible combinations of concrete and sand for this order are given by this system of inequalities, where c = pounds of concrete and s = pounds of sand: 6c + 2s ≤ 2,500 4.50c + 3s ≥ 2,750 Which graph's shaded region represents the possible combinations of concrete and sand for this order?

Mathematics
1 answer:
yaroslaw [1]2 years ago
5 0

Answer: The below graph's shaded region represents the possible combinations of concrete and sand for this order

Step-by-step explanation:

Here, the system of inequality that represents the given situation is,

6c + 2s ≤ 2,500 --------(1)

4.50c + 3s ≥ 2,750 -------(2)

Where c = pounds of concrete,

s = pounds of sand

Now, The related equation of the above inequalities are,

6c + 2s = 2500

4.50c + 3s = 2750

By solving the above equations,

We get, c =222.\bar{2}, s = 583.\bar{3}

Thus, the intersection point of the inequalities = (222.\bar{2}, 583.\bar{3})

Now, At (0,0) ,

inequality (1), 6×0 + 2×0≤ 2500 ⇒ 0 ≤ 2500 ( true)

Hence, the shaded region of inequality contains the origin.

Similarly, At (0,0), inequality (2) is false,

⇒ The shaded region of inequality (2) does not contain the origin.

Thus, By the above explanation we can plot the shaded region of the system of the given inequalities.

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2 years ago
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â  Suppose a small group of 11 Allen's humming
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Answer:

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3.15 represent the sample mean

\mu population mean (variable of interest)

\sigma=0.38 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that z_{\alpha/2}=1.28

Now we have everything in order to replace into formula (1):

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

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Answer:

x= (y+40)-(y-330)

Step-by-step explanation:

According to the information provided, the difference in their scores would be the result of subtracting Austin's SAT score from Alexandra's SAT score.

Then, as Alexandra's SAT score was 40 points above the average score this means that you have to add 40 to the average score to get her result. Also, as Austin's SAT score was 330 points below the average score, this means that you have to subtract 330 from the average score. With this you can write the expression:

x= difference in their scores

y= average score

x= (y+40)-(y-330)

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