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I am Lyosha [343]
3 years ago
7

A hardware store orders at most $2,500 worth of concrete and sand. The store needs to make a profit of at least $2,750 on the or

der. The possible combinations of concrete and sand for this order are given by this system of inequalities, where c = pounds of concrete and s = pounds of sand: 6c + 2s ≤ 2,500 4.50c + 3s ≥ 2,750 Which graph's shaded region represents the possible combinations of concrete and sand for this order?

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0

Answer: The below graph's shaded region represents the possible combinations of concrete and sand for this order

Step-by-step explanation:

Here, the system of inequality that represents the given situation is,

6c + 2s ≤ 2,500 --------(1)

4.50c + 3s ≥ 2,750 -------(2)

Where c = pounds of concrete,

s = pounds of sand

Now, The related equation of the above inequalities are,

6c + 2s = 2500

4.50c + 3s = 2750

By solving the above equations,

We get, c =222.\bar{2}, s = 583.\bar{3}

Thus, the intersection point of the inequalities = (222.\bar{2}, 583.\bar{3})

Now, At (0,0) ,

inequality (1), 6×0 + 2×0≤ 2500 ⇒ 0 ≤ 2500 ( true)

Hence, the shaded region of inequality contains the origin.

Similarly, At (0,0), inequality (2) is false,

⇒ The shaded region of inequality (2) does not contain the origin.

Thus, By the above explanation we can plot the shaded region of the system of the given inequalities.

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Answer:

$34.8

Step-by-step explanation:

Given data

Cost of apartment= $870 per month

increase= 20%

Discount= 8%

Let us find the amount of increase

=20/100*870

=0.2*870

=$174

New cost = 870+174

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New cost of apartment for 18 month

=1044*18

=$18792

He gave them 8% discount

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=0.8*18792

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Hence the monthly fee will be

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Therefore the difference in price is

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3 years ago
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borishaifa [10]
<h3>Given</h3>

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<h3>Find</h3>

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... x + 2 -2 ≥ 6 -2

... x ≥ 4 . . . . . . . . . . simplify

The answer is read, "x is greater than or equal to 4." This means the solution is those real numbers that are to the right of 4 on the number line, and including 4 on the number line. Numbers to the left of 4 are <em>not included</em>. The inclusion of the number 4 is shown by putting a solid dot there (not an open circle).

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The given operation involves just swapping the two rows, so carrying out R_1\leftrightarrow R_2 on the matrix gives

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6 0
3 years ago
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