Help me with this question please

Mathematics

1 answer:

Leokris [45]2 years ago

4 0

Answer:

14s^4-7s^2+15

Step-by-step explanation:

At the beginning the only bracket that is changing is the 3rd one because of the minus. (12s^4-6s^2+4s)+(6s^4-4s+27)-4s^4+s^2+12 then open the rest of the brackets. And start calculating.i will just to show you which ones u calculate together. (I'll separate the numbers depending on what they're squared to).

12s^4+6s^4-4s^4=14s^4

-6s^2-s^2=7s^2

27-12=15

All together is 14s^4-7s^2+15

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Reduce then calculate 7/8 x 4/15 x 3/7 = ? <br><br> Can you help?

Zepler [3.9K]

since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.

$\bf \cfrac{7}{8}\times \cfrac{4}{15}\times \cfrac{3}{7}\implies \cfrac{7}{7}\times \cfrac{4}{8}\times \cfrac{3}{15}\implies \cfrac{1}{1}\times \cfrac{1}{2}\times \cfrac{1}{5}\implies \cfrac{1\cdot 1\cdot 1}{1\cdot 2\cdot 5}\implies \cfrac{1}{10}$