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son4ous [18]
2 years ago
11

Help me with this question please

Mathematics
1 answer:
Leokris [45]2 years ago
4 0

Answer:

14s^4-7s^2+15

Step-by-step explanation:

At the beginning the only bracket that is changing is the 3rd one because of the minus. (12s^4-6s^2+4s)+(6s^4-4s+27)-4s^4+s^2+12 then open the rest of the brackets. And start calculating.i will just to show you which ones u calculate together. (I'll separate the numbers depending on what they're squared to).

12s^4+6s^4-4s^4=14s^4

-6s^2-s^2=7s^2

27-12=15

All together is 14s^4-7s^2+15

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5 kilograms of coffee are going to be shared equally among 4 people.
kherson [118]

Step-by-step explanation:

I'm not sure if this will help but to find out how much coffee 4 people would need you would have to divide 4 into 5 which is 1 1/5

EQUATION-- 4/5= X

I chose that because / means divide 5 into 4 would give you x we don't know what x is until we actually do the problem

Even if im not correct I hope it helped a bit

5 0
2 years ago
Which graph below has a “period” of 4?
Inessa [10]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
Area of paralellogram with base 15cm and height12cm
azamat

Answer:

180 cm2

Area of a polyhedron:

15(=base)x12(=height)

=180cm2

btw parallelogram is a 2D pic how you can come out a ''base'' and ''height''? It should be called a polyhedron. Your question is weird.

If so, your ''area of parallelogram'' is 15cm2 since your question is hecking  weird.

Btw it's 15cm2 not 15

Please check ur question b4 u ask

7 0
2 years ago
Read 2 more answers
20 POINTS PLEAE HELP!!!!!!!!!!!!!!!
Alina [70]
His first payment is $100, thus a₁ = 100.

the next "term", month will be 1.1 times more than the one before, namely r = 1.1, the common ratio.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=100\\
r=1.1\\
n=20
\end{cases}

\bf \sum\limits_{i=1}^{20}~100(1.1)^{i-1}\qquad \qquad\qquad  \qquad S_{20}=100\left( \cfrac{1-1.1^{20}}{1-1.1} \right)
\\\\\\
S_{20}=100\left( \cfrac{1-\stackrel{\approx}{6.727499949}}{-0.1} \right)\implies S_{20}\approx 100(57.27499949)
\\\\\\
S_{20}\approx 5727.4999493256

is the serie divergent or convergent?

well, to make it short, when the common ratio is 0 < | r | < 1, namely a fraction between 0 and 1, only then the serie is convergent, namely it reaches a fixed value, now in this case, 1.1 is a value larger than anything between 0 and 1, so no dice.
5 0
3 years ago
Read 2 more answers
Meghan used her cell phone for 45 minutes each day for n days. Her total minutes of cell phone usage was 540 minutes. Write an e
makvit [3.9K]

Answer:

Is there answer options because if not then it would possibly be y = 45x + 540 or it could be 45x = 540 or it could be 45x/540 so it can be any of those :)

Step-by-step explanation:

3 0
3 years ago
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